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lara [203]
2 years ago
14

How did Robert Whitaker change dassification?

Chemistry
1 answer:
tester [92]2 years ago
3 0

Answer:

created an organizational hierarchy

Explanation:

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barxatty [35]

<em>Same group element have same</em><em><u> Valence electron</u></em><em> and behave similarly in </em><em><u>Chemistry.</u></em>

<u>Explanation:</u>

For example. First group elements Alkali metals:- H, Li, K, Rb, Cs, Fr

Valance electron will take part in forming a bond with other elements and compound will form. All the above-given elements (H-Fr) have valence electron 1 in outer most 'S' shell. All have electronic configuration S1

Behavior: Since valence electrons are the same so the behavior of all the elements in this group is the same. All are metal (from Li-Fr, except Hydrogen), all are very reactive, does not found in native state in the environment, and all react with water.

4 0
3 years ago
The dimensions of a cupboard are 1.31 m wide
Mnenie [13.5K]

Answer:

The volume of cupboard is 2.0043 m³.

Explanation:

Given data:

width of cupboard = 1.31 m

length of cupboard = 0.9 m

height of cupboard = 1.70 m

Volume = ?

Solution:

Volume = length × width × height

Volume = 0.9 m × 1.31 m × 1.70 m

Volume = 2.0043 m³

The volume of cupboard is 2.0043 m³.

4 0
3 years ago
Read 2 more answers
What type of pollution in cities composed of car exhaust and industrial pollutes
Troyanec [42]
Air pollution is the answer

4 0
3 years ago
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Briskly meaning
Tju [1.3M]

Answer:

You need follower?

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4 0
3 years ago
Read 2 more answers
at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a p
Alex

Answer:

initial temperature=-3.31^{\circ}C

Explanation:

Assuming that the given follows the ideal gas nature;

P_1=0.723atm

V_1=13.5L

T_1=?

P_2=0.612atm

V_2=17.8L

T_2=28 ^{\circ}C =273+28K=301K

mole of gass will remain same at any emperature:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

putting all the value we get:

T_2 =269.7K =-3.31 ^{\circ} C

initial temperature=-3.31^{\circ}C

6 0
3 years ago
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