Which point has the greatest electric potential energy?

Which best describes the relationship between humidity and air pressure?

spayn [35]

Answer:<span>Humid air is lighter, so it has lower pressure.

The reason is the molecules of water are H2O, whose molar mass is 18 g/mol.

These molecules displaces molecules of N2 and O2, whose molar masses are:

N2: 2*14g/mol = 28 g/mol, and
O2: 2*16g/mol = 32 g/mol.

Then molecules of 28g/mol and 32 g/mol are being replaced with molecules of 18g/mol, leading to a lower weight of the same volume of air, which results in lower pressure.
</span>

5 0

3 years ago

Read 2 more answers

Pls reply... plss!! help me

viktelen [127]

Answer:

this is your solution

Explanation:

Answer-1 Iodine

Answer-2 Uterus

Answer-3 Adam's Apple

Answer-4 Distance

Answer-5 Carbon dioxide

Answer-6 Zygote

7 0

3 years ago

Which statement is correct?

slega [8]

Answer:B

Explanation:

Galilean transformation are only approximately correct,while Lorentz transformation are more exact

6 0

3 years ago

Read 2 more answers

A parallel-plate capacitor has square plates that have edge length equal to 1.20×102cm and are separated by 1.00 mm. It is conne

lora16 [44]

Answer:

Energy stored in the capacitor will be $1.835\times 10^{-6}J$

Explanation:

We have given edge length of capacitor = $1.2\times 10^2cm=1.2m$

So area A = 1.2×1.2 = 1.44 $m^2$

Separation is given as d 1 mm = $10^{-3}m$

We know that capacitance is given by $C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 1.44}{10^{-3}}=12.744\times 10^{-9}F$

Voltage is given as V = 12 volt

We know that energy stored is given by $E=\frac{1}{2}CV^2=\frac{1}{2}\times 12.744\times 10^{-9}\times 12^2=1.835\times 10^{-6}J$

3 0

4 years ago

Read 2 more answers

An accepted value for the acceleration due to gravity is 9.801 m/s2. In an experiment with pendulums, you calculate that the val

Fed [463]

g Generally the accepted value of acceleration due to gravity is 9.801 $m/s^2$

as per the question the acceleration due to gravity is found to be 9.42 $m/s^2$ in an experiment performed.

the difference between the ideal and observed value is 0.381.

hence the error is - $\frac{0.381}{9.801} *100$

=3.88735 percent

the error is not so high,so it can be accepted.

now we have to know why this occurs-the equation of time period of the simple pendulum is give as- $T=2\pi\sqrt[2]{l/g}$

$g=4\pi^2\frac{l}{T^2}$

As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.

if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801 $m/s^2$

5 0

4 years ago