Answer:
Force exerted by the lighter block on the heavier block is 6.63 N
Explanation:
Given Data
F = 80N
m = 1kg
M = 11kg
Solution:
*We assume that there is no friction
Calculating the acceleration of the system
a =
a =
a =
a = 6.67m
Let's write the Equation of Motion of the heavier block
= F -
Ma = F -
force exerted by the lighter block on the heavier block is calculated as
= F - Ma
= 80 - (11 x 6.67)
= 6.63 N
Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:
Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.
where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:
1) Do > 2f
Do means object distance
2f means 2 x focal length
2 x focal length = radius of curvature
When an object is placed beyond the radius of curvature, a real image is formed between the radius of curvature and focus. The image size is reduced. The sketch is shown below
