All categories

4 years ago

Does Liquid HF conduct electricity?What is the reason for your answer?

Chemistry

1 answer:

liq [111]4 years ago

6 0

Answer:

Does liquid HF conduct electricity?

Explanation:

HF is the precursor to elemental fluorine, F2, by electrolysis of a solution of HF and potassium bifluoride. The potassium bifluoride is needed because anhydrous HF does not conduct electricity.

You might be interested in

Into a 0.25 M solution of Ba3(PO4)2(aq), excess Na2SO4(aq) was added to form BaSO4(s). Ba3(PO4)2(aq) + 3Na2SO4(aq) → 3BaSO4(s) +

kogti [31]

Answer:

Answer is in the explanation.

Explanation:

For the reaction:

Ba₃(PO₄)₂(aq) + 3Na₂SO₄(aq) → 3BaSO₄(s) + 2Na₃PO₄(aq)

As Na₂SO₄(aq) is in excess, limiting reactant is Ba₃(PO₄)₂(aq). As the molarity of the solution is 0,25M and you knew the volume of the solution, you can obtain the moles of Ba₃(PO₄)₂ doing 0,25M×volume.

As 1 mol of Ba₃(PO₄)₂(aq) react with 3 moles of BaSO₄ the moles of BaSO₄ are three times moles of Ba₃(PO₄)₂.

As BaSO₄ molar mass is 233,38g/mol. The mass of BaSO₄ is given by moles of BaSO₄ × 233,38g/mol

I hope it helps!

6 0

3 years ago

The weight of the body decrease inside water why?

Lady_Fox [76]

Penurunan atau kehilangan massa otot bisa menimbulkan penurunan berat badan yang tidak direncanakan

3 0

3 years ago

Cu + 2AgNO3 mc021-1.jpg Cu(NO3)2 + 2Ag The molar mass of Cu is 63.5 g/mol. The molar mass of Ag is 107.9 g/mol. What mass, in gr

Ray Of Light [21]

31.79 g Cu / 63.5 g/mol Cu ---> 0.5
0.5 * (2/1) ---> 1
1 * 107.9 g/mol Ag

107.9 grams

5 0

3 years ago

Read 2 more answers

How do the individual concepts covered in Stoichiometry contribute to writing a balanced equation?

valkas [14]

Answer:

The coefficients of a balanced chemical equation tell us the relative number of moles of reactants and products. All stoichiometric calculations begin with a balanced equation. Balanced equations are necessary because mass is conserved in every reaction. ... This is the reactant that is completely used in the reaction.

Explanation:

5 0

3 years ago

A natural water with a flow of 3800 m3/d is to be treated with an alum dose of 60 mg/L. Determine the chemical feed rate for the

svet-max [94.6K]

Explanation:

First, we will calculate the feed rate of alum as follows.

$\frac{\text{60 mg alum}}{\text{1 L water}} \times \frac{\text{1000 L water}}{1 m^{3}} \times \frac{3800 m^{3}}{day} \times \frac{\text{1 g alum}}{\text{1000 mg alum}}$

= 228000 g/day

Converting this amount into g/min as follows.

$\frac{228000 g}{1 day} \times \frac{1 day}{1440 min}$

= 158 g/min

Now, the chemical equation will be as follows.

$Al_{2}(SO_{4})_{3}.14H_{2}O \rightarrow 2Al(OH)_{3}(s) + 6H^{+} + 3SO^{2-}_{4} + 8H_{2}O$

$\frac{\text{30 mg alum}}{1 L} \times \frac{\text{1 mmol alum}}{\text{594 mg alum}} \times \frac{\text{3 mmol SO^{2-}_{4}}}{\text{1 mmol alum}}$

= 0.151 mmol $mmol SO^{2-}_{4}/L$

$\frac{0.151 mmol SO^{2-}_{4}}{L} \times \frac{\text{2 meq SO^{2-}_{4}}}{\text{1 mmol SO^{2-}_{4}}} \times \frac{\text{1 meq Alk}}{\text{1 meq SO^{2-}_{4}}} \times \frac{\text{50 mg CaCO_{3}}}{\text{1 meq Alk}}$

= 15.15 mg $CaCO_{3}$ /L

For precipitate:

$Al_{2}(SO_{4})_{3}.14H_{2}O \rightarrow 2Al(OH)_{3}(s) + 6H^{+} + 3SO^{2-}_{4} + 8H_{2}O$

$\frac{\text{30 mg alum}}{1 L} \times \frac{\text{1 mmol alum}}{\text{594 mg alum}} \times \frac{\text{2 mmol Al(OH)_{3}}}{\text{1 mmol alum}} \times \frac{\text{78 mg Al(OH)_{3}}}{\text{1 mmol Al(OH)_{3}}}$

= 7.88 $Al(OH)_{3}/L$

$\frac{7.88 mg Al(OH)_{3}}{1 L} \times \frac{3800 m^{3}}{1 day} \times \frac{1000 L}{1 m^{3}} \times \frac{1 kg}{10^{6} mg}$

= 29.9 $Al(OH)_{3}/day$

3 0

4 years ago

Does Liquid HF conduct electricity?What is the reason for your answer?​

Does Liquid HF conduct electricity?What is the reason for your answer?