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melisa1 [442]
2 years ago
7

The minimum energy required to break the oxygen-oxygen bond in oxygen is 495 kJ/mol. What is the longest wavelength of radiation

that possesses the necessary energy to break this bond? What type of electromagnetic radiation is this?
Chemistry
1 answer:
Sergeeva-Olga [200]2 years ago
4 0

Answer:

241 nm, it is UV light range

Explanation:

The minimum energy needed required to break the oxygen-oxygen bond = 495 kJ/mol

Energy needed for 1 molecule of oxygen = 495 × 10³ J / avogadro's constant = 495 × 10³ J  / ( 6.02 × 10²³) = 8.223 × 10⁻¹⁹ J

Energy = hv

where h = Planck constant = 6.626 × 10 ⁻³⁴ m²kg/s and v = frequency

c speed of light = vλ

c / λ = v

E = hc / λ

λ  = hc / E = (6.626 × 10 ⁻³⁴ m²kg/s × 3.0 × 10 ⁸ m/s) / (8.223 × 10⁻¹⁹ J)  = 2.41 × 10⁻⁷m = 241 nm

UV light wavelength is between 400 nm - 10 nm

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3 years ago
Read 2 more answers
How many milliliters of 0.2560 M KCl solution will contain 20.00 g of KCl?
lutik1710 [3]

Answer:

1048 mL

Explanation:

Step 1: Given data

  • Concentration of the solution: 0.2560 M
  • Mass of KCl (solute): 20.00 g

Step 2: Calculate the moles corresponding to 20.00 g of KCl

The molar mass of KCl is 74.55 g/mol.

20.00 g × 1 mol/74.55 g = 0.2683 mol

Step 3: Calculate the volume of the solution

Molarity is equal to moles of solute divided by liters of solution.

M = moles of solute / volume of solution

volume of solution = moles of solute / M

volume of solution = 0.2683 mol / (0.2560 mol/L)

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