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erastova [34]
4 years ago
14

As a change of state takes place, heat and temperature

Chemistry
1 answer:
Alexeev081 [22]4 years ago
5 0

Answer:

c. stays the same, changes

Explanation:

temperature and heat go hand in hand, however while the change of state occurs, the temperature remains the same while the heat increases since the heat input is constant.

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Use dimensional analysis to solve the following problems. Pay attention to correct use of units and correct use of significant f
umka21 [38]

Answer:

1) 0.00498 mol Cu.

2) 0.00000374 mol CO₂

Explanation:

Question 1)

We want to convert 3.00 * 10²¹ copper atoms into moles. Note that 3.00 is three significant figures.

Recall that by definition, one mole of a substance has exactly 6.022 * 10²³ amount of that substance. In other words, we have the ratio:

\displaystyle \frac{1\text{ mol}}{6.022\times 10^{23} \text{ Cu}}

We are given 3.00 * 10²¹ Cu. To cancel out the Cu, we can multiply it by our above ratio with Cu in the denominator. Hence:

\displaystyle 3.00 \times 10^{21} \text{ Cu} \cdot \frac{1\text{ mol Cu}}{6.022\times 10^{23} \text{ Cu}}

Cancel like terms:

=\displaystyle 3\times 10^{21} \cdot \frac{1\text{ mol Cu}}{6.022\times 10^{23} }

Simplify:

\displaystyle  = \frac{3\text{ mol Cu}}{6.022 \times 10^{2}}

Use a calculator:

= 0.004981... \text{ mol Cu}

Since the resulting answer must have three significant figures:

= 0.00498\text{ mol Cu}

So, 3.00 * 10²¹ copper atoms is equivalent to approximately 0.00498 moles of copper.

Question 2)

We want to convert 2.25 * 10¹⁸ molecules of carbon dioxide into moles. Note that 2.25 is three significant digits.

By definition, there will be 6.022 * 10²³ carbon dioxide molecules in one mole of carbon dioxide. Hence:

\displaystyle \frac{6.022 \times 10^{23} \text{ CO$_2$}}{1\text{ mol CO$_2$}}

To cancel the carbon dioxide from 2.25 * 10¹⁸, we can multiply it by the above ratio with the carbon dioxide in the denominator. Hence:

\displaystyle 2.25\times 10^{18} \text{ CO$_2$} \cdot \frac{1\text{ mol CO$_2$}}{6.022\times 10^{23} \text{ CO$_2$}}

Cancel like terms:

\displaystyle= 2.25\times 10^{18} \cdot \frac{1\text{ mol CO$_2$}}{6.022\times 10^{23}}

Simplify:

\displaystyle = \frac{2.25 \text{ mol CO$_2$}}{6.022\times 10^5}}

Use a calculator:

=0.000003736...\text{ mol CO$_2$}

Since the resulting answer must have three significant figures:

= 0.00000374\text{ mol CO$_2$}

So, 2.25 * 10¹⁸ molecules of carbon dioxide is equivalent to approximately 0.00000374 moles of carbon dioxide.

4 0
3 years ago
Read 2 more answers
Suppose a species of snake is living in a certain area. Some of the snakes in the population are black and some are orange. Over
dybincka [34]

Answer:

The black snakes will survive and reproduce while the orange snakes die out.

Explanation:

The orange snakes will be easier to see by their prey and predators, and therefore will die out while the black snakes thrive because of their camouflage.

6 0
3 years ago
Read 2 more answers
The formulas for ethane, ethene, and ethyne are C 2 H 6 C2H6 , C 2 H 4 C2H4 , and C 2 H 2 C2H2 , respectively. Rank these compou
Anuta_ua [19.1K]

Answer:

Ethane (1.09 A) > Ethene(1.076 A) > Ethyne(1.06 A)

Explanation:

The types of bonds present are:

a) Ethane : single bond

b) Ethene : double bond (one sigma one pi)

c) Ethyne: triple bond (one sigma and two pi bonds)

More the number of bonds lesser the bond length.

Thus the order of bond length of carbon-carbon bond will be:

Ethane (1.09 A) > Ethene(1.076 A) > Ethyne(1.06 A)

6 0
4 years ago
Which of the following is NOT a clue that could indicate a chemical change?
mixer [17]

Answer:

i think its C, but im not 100% sure. if not c, then D, but C sounds more right.

Explanation:

everything else sounds like sure fire sighs of a chem change. good luck

6 0
3 years ago
A new penny has a mass of 2.49 grams and occupies 0.349 cm cubed. If pure copper has a density of 8.96 g/cm cubed, is the new pe
lys-0071 [83]

Answer: The new penny is not pure copper

Explanation:

Density \rho is defined as a relation between the mass m and the volume V:

\rho=\frac{m}{V}

Now, we are told the density of pure copper is:

\rho_{copper}=8.96 g/cm^{3}

And we are given the mass and volume of the new penny, with which we can calculate its density:

\rho_{penny}=\frac{m_{penny}}{V_{penny}}=\frac{2.49 g}{0.349 cm^{3}}

\rho_{penny}=7.13 g/cm^{3} As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.

8 0
4 years ago
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