The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
Answer: The final temperature of nickel and water is
.
Explanation:
The given data is as follows.
Mass of water, m = 55.0 g,
Initial temp,
,
Final temp,
= ?,
Specific heat of water = 4.184
,
Now, we will calculate the heat energy as follows.
q = 
= 
Also,
mass of Ni, m = 15.0 g,
Initial temperature,
,
Final temperature,
= ?
Specific heat of nickel = 0.444 
Hence, we will calculate the heat energy as follows.
q = 
=
Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

= -(
)
= 
Thus, we can conclude that the final temperature of nickel and water is
.
Explanation:
mass = moles * molar mass
molar mass of carbon dioxide (CO2) = 12+32 = 44
= 19.5* 44 = 858
proof
moles = mass /molar mass
= 858/44 = 19.5 moles
Answer:
Sulphur
Explanation:
Sulphur(S) is the Sixteenth element of the periodic table and it has an electronic configuration of 2,8,6. This means it has six electrons in its outermost shell( valence electrons).
Sulphur has sixteen(16) protons which is equal to the atomic number which is also sixteen. Sulphur ends with the letter ‘r’. All the descriptions of the element are satisfied and it validates Sulphur.