Answer:
The pressure of N₂O₄ in the reaction vessel after the reaction is 290 mmHg
Explanation:
Nitrogen gas reacts with oxygen gas to form dinitrogen tetroxide.
N₂ (g) + 2O₂ (g) → N₂O₄ (g)
Therefore since by Avogadro's law equal volumes of all gases contain equal numbers of molecules, there fore as the gases are within the same vessel, thier partial pressure is equivalent to their concentration
from the reaction, 1 mole of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄
Thus
1 mmHg of N₂ react with 2 mmHg of O₂ to produce 1 mmHg of N₂O₄
337 mmHg N₂ ×(1 mmHg of N₂O₄/ 1 mmHg of N₂) = 337 mmHg N₂O₄
580 mmHg O₂ ×(1 mmHg of N₂O₄/ 2 mmHg of O₂) = 290 mmHg N₂O₄
As seen from the above calculation, the limting reactant is oxygen and the partial pressure of N₂O₄ = 290 mmHg
Answer:did u ever get the answer
Explanation:i have a homework to do
I don't know much about this, but probably the reason why your teacher circled 300k is because of what's in the photo below. If you couldn't tell from the photo, its because 300k isn't negative. Anyway this is my guess, based on my limited knowledge.
Answer:
1.67 ×10²³ atoms of hydrogen present in 2.5 g of water.
Explanation:
Given data:
Mass of water = 2.5 g
Number of hydrogen atoms= ?
Solution:
First of all we will calculate the molar mass of water.
Molar mass of H₂O = 16 +1 ×2 = 18 g/mol
The number of atoms will be determine through the Avogadro number.
The number 6.022×10²³ is called Avogadro number and it is the number of atoms or molecules in one gram of atoms of an element or one gram molecules of a compound.
First of all we will calculate the number of moles of water in 2.5 g.
Number of moles = mass /molar mass
Number of moles = 2.5 g / 18 g/mol
Number of moles = 0.139 mol
The number of molecules of water in 10 g.
0.139 × 6.022×10²³ = 0.837 ×10²³molecules
one water molecule contain two hydrogen atoms. For 0.837×10²³ molecules,
0.837×10²³× 2 = 1.67 ×10²³ atoms
Answer:
probably because most of our food comes from animals-
Explanation: