Answer:
Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.
Explanation:
Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.
Respuesta:
2400 mL
Explicación:
Paso 1: Información dada
- Volumen de solución: 3 L (3000 mL)
- Concentración de naranja: 20 % v/v
Paso 2: Calcular el volumen de naranja
La concentración de naranja es de 20 % v/v, es decir, cada 100 mL de solución hay 20 mL de naranja.
3000 mL Sol × 20 mL Naranja/100 mL Solución = 600 mL Naranja
Paso 3: Calcular el volumn de agua
El volumen de soluciónes igual a la suma de los volúmenes de naranja y agua.
VSolución = VNaranja + VAgua
VAgua = VSolución - VNaranja
VAgua = 3000 mL - 600 mL = 2400 mL
C
Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.
Explanation:
The energy of a wave is given by the formula;
E= hf
Whereby;
E = energy
h = Plank’s constant
f = frequency
Remember that f can be also represented as;
¹/ λ
Whereby;
λ = wavelength
Wavelength and frequency are therefore inversely proportional.
Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.
Learn More:
For more on frequency and wavelength of waves check out;
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Answer:
The higher up an object is the greater its gravitational potential energy. ... As most of this GPE gets changed into kinetic energy, the higher up the object starts from the faster it will be falling when it hits the ground. So a change in gravitational potential energy depends on the height an object moves through.