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kati45 [8]
4 years ago
8

Good experimental design includes a hypothesis that is

Physics
2 answers:
scZoUnD [109]4 years ago
7 0

Answer: testable and observable.

Explanation:

Experimental design includes the concepts which are directly related to the plan which is required to be followed so as to deduce a reasonable outcome. It must include a hypothesis which should be testable and observable on the basis of application of suitable scientific methodology. A hypothesis is presumed statement related to a particular natural phenomena or event which is required to be proved by implementation of scientific experimentation procedure and direct observation.

Ratling [72]4 years ago
3 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Good experimental design includes a hypothesis that is <span>testable and observable.</span>
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To reduce friction on an aircraft, the surfaces (skin) are ? and the body is ?
bagirrra123 [75]

Answer:

Surface (skin) should be smooth and body should be streamlined shaped.

4 0
2 years ago
Why should we not use nuclear energy
Softa [21]

Answer:

Barriers to and risks associated with an increasing use of nuclear energy include operational risks and the associated safety concerns, uranium mining risks, financial and regulatory risks, unresolved waste management issues, nuclear weapons proliferation concerns, and adverse public opinion.

Explanation:

5 0
3 years ago
If you measure the mass of a model car to be 230 grams, but the actual mass is 218 grams, what is your percent error?
konstantin123 [22]

Mass of a model car you measured = 230 grams

Actual mass = 218 grams

Percent error = ?

First subtract the actual value from the value you measured,

230 grams – 218 grams = 12 grams

Now divide 12 grams by the actual mass that is 218 grams:

12 / 218 = 0.055                             

Now multiply 0.055 with 100 to get the percent error;

0.055 x 100 = 5.5%

So, the Percent error is 5.5%.

8 0
4 years ago
What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i
kondor19780726 [428]

Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

Initial speed of car =u=96 km/h=96\times \frac{5}{18}=26.67m/s

1km/h=\frac{5}{18}m/s

Final speed of car=v=56km/h=56\times \frac{5}{18}=15.56m/s

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

v^2-u^2=2as

(15.56)^2-(26.67)^2=2a(55)

-469.18=110a

a=\frac{-469.18}{110}=-4.27m/s^2

Where negative sign indicates that velocity of car decreases.

Work done by a car's barking system=w=F\times s=ma\times s

Work done by a car's barking system=1500\times -4.27\times 55=352275J

Work done by a car's barking system=-\frac{352275}{1000}=-352.275KJ

1KJ=1000J

Where negative sign indicates that work done in opposite direction of motion.

7 0
4 years ago
Read 2 more answers
The Jamaican bobsled team was moving at a velocity of 50 m/s, then they hit the brakes on their sled to decelerate at a uniform
atroni [7]

Answer:

The time it took the bobsled to come to rest is 10 s.

Explanation:

Given;

initial velocity of the bobsled, u = 50 m/s

deceleration of the bobsled, a = - 5 m/s²

distance traveled, s = 250 m

Apply the following kinematic equation to determine the time of motion of the bobsled;

s = ut + ¹/₂at²

250 = 50t + ¹/₂(-5)t²

250 = 50t - ⁵/₂t²

500 = 100t - 5t²

100 = 20t -t²

t² - 20t + 100 = 0

t² -10t - 10t + 100 = 0

t (t - 10) - 10(t - 10) = 0

(t - 10)(t - 10) = 0

t = 10 s

Therefore, the time it took the bobsled to come to rest is 10 s.

3 0
3 years ago
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