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Daniel [21]
3 years ago
13

A plane starting from rest (vo = 0 m/s) when t0 = 0s. The plane accelerates down the runway, and at 29 seconds, its velocity is

+72.2 m/s. (+ indicates to the right). Determine the average acceleration for the plane.
Physics
1 answer:
IrinaK [193]3 years ago
4 0

Answer:

Acceleration, a=2.48\ m/s^2

Explanation:

Given that,

The plane is at rest initially, u = 0

Final speed of the plane, v = 72.2 m/s

Time, t = 29 s

We need to find the average acceleration for the plane. It can be calculated as :

a=\dfrac{v-u}{t}

a=\dfrac{72.2}{29}

a=2.48\ m/s^2

So, the average acceleration for the plane is 2.48\ m/s^2. Hence, this is the required solution.

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1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is
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Newtown third law applies to blank of objects​
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