Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t + a t²
In this question u = 0 , because car was at rest initially
Thus S = a t²
here S is displacement and a is the acceleration of car
Therefore 360 = a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a =
or a = 0.2 m s⁻²
Answer:
The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.
Explanation:
By Principle of Energy Conservation and Work-Energy Theorem we present the equations that describe the situation of the roller coaster car on each top of the hill. Let consider that bottom has a height of zero meters.
From top of the first hill to the bottom
(1)
From the bottom to the top of the second hill
(2)
Where:
- Mass of the roller coaster car, in kilograms.
- Speed of the roller coaster car at the bottom between the two hills, in meters per second.
- Gravitational acceleration, in meters per square second.
- Height of the first top of the hill with respect to the bottom, in meters.
- Work done by non-conservative forces on the car between the top of the first hill and the bottom, in joules.
- Speed of the roller coaster car at the top of the second hill, in meters per seconds.
- Height of the second top of the hill with respect to the bottom, in meters.
- Work done by non-conservative forces on the car bewteen the bottom between the two hills and the top of the second hill, in joules.
By using (1) and (2), we reduce the system of equation into a sole expression:
(3)
Where is the work done by non-conservative forces on the car from the top of the first hill to the top of the second hill, in joules.
If we know that ,
,
,
and
, then the work done by non-conservative force is:
The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.