Answer
Time period T = 1.50 s
time t = 40 s
r = 6.2 m
a)
Angular speed ω = 2π/T
=
= 4.189 rad/s
Angular acceleration α =
=
= 0.105 rad/s²
Tangential acceleration a = r α = 6.2 x 0.105 = 0.651 m/s²
b)The maximum speed.
v = 2πr/T
=
= 25.97 m/s
So centripetal acceleration.
a =
=
= 108.781 m/s^2
= 11.1 g
in combination with the gravitation acceleration.
Answer:
205N
Explanation:
The net force (F) is the difference between the applied force() and the kinetic frictional force(
). i.e
F = -
-----------------(i)
Note that;
= μmg
Where;
μ = coefficient of kinetic friction
m = mass of the body
g = acceleration due to gravity = 10m/s²
Equation (i) then becomes;
F = - μmg -------------------(ii)
<em>Given from question;</em>
m = mass of motorcycle = 150kg
μ = 0.03
= 250N
Substitute these values into equation (ii) as follows;
F = 250 - (0.03 x 150 x 10)
F = 250 - (45)
F = 205N
Therefore, the net force applied to the motorcycle is 205N