A neutral atom has the same number of _____ in it’s nucleus as____ in its electron cloud
1 answer:
You might be interested in
<span>Halflife is the time needed for a radioactive molecule to decay half of its current mass. If t is the time elapsed, the formula for the halflife would be:
final mass= original mass * </span>
<span>
If you put the information of the problem into the formula, the equation will be:
</span>final mass= original mass *
final mass= 800g *
final mass= original mass * </span>
<span>
If you put the information of the problem into the formula, the equation will be:
</span>final mass= original mass *
final mass= 800g *
Answer:
1. 1 × 10⁻²
Explanation:
Given that:
Temperature = 335 ° C = (335+ 273)K = 608
Pressure = 0.750 atm
Volume = 1 Litre
number of moles of NO2 = ???
Rate Constant =0.0821 L atm /K/mol
Using the Ideal gas equation
PV = nRT
n =
n =
n = 0.015
n = 1.5 × 10⁻² mole
Density = 0.525 g/L
The equation for the reaction can be illustrated as:
2NO2(g) ⇌ 2NO(g) + O2(g)
For the ICE table; we have:
Initial x 0 0
Change -2y + 2y +y
Equilibrium (x - 2y) 2y y
Total moles at equilibrium = (x-2y)+2y+y
= x + y moles
However,
1.5 × 10⁻² mole of the mixture has a mass of 0.525 g
i.e x + y moles = 1.5 × 10⁻² mole
Now, molar mass of 1 mole of NO2 = 46g/mol
Since number of moles =
mass of (x-2y) moles = 46 × (x-2y) g
Molar mass of NO = 30 g/mol
Also, mass of NO = 2y × 30 = 60y
Molar mass of O2 = 32 g/mol
Mass of O2 = y × 32 = 32y
Total mass = ( 46x - 90y)+60y+32y = 0.525
46x = 0.525
x =
x = 0.0114
x = 1.14 × 10⁻²
x + y moles = 1.5 × 10⁻²
y = 1.5 × 10⁻² - 1.14 × 10⁻²
y = 0.0036
y = 3.6 × 10⁻³
At equilibrium
[NO2] = ( 1.14 - 2(0.36))× 10⁻² = 4.2 × 10⁻³ M
[NO] = 2 ( 3.6 × 10⁻³) = 7.2 × 10⁻³ M
[O2] = 3.6 × 10⁻³ M
0.011
1. 1 × 10⁻²
Neutralization reaction takes place between an acid and a base to form salt and water.
In the given reaction the acid is hydrochloric acid HCl and the base is aluminum hydroxide (Al(OH)).
The correct balanced equation for the neutralization reaction that occurs between aluminum hydroxide and hydrochloric acid can be represented as:
Al(OH)can give 3 hydroxide,
ions which can neutralize the 3
ion produced by 3 HCl molecules giving 3 mole of water and the salt aluminum chloride, AlCl
.
Therefore the correct option will be.
D. Al(OH)3 + 3 HCl (aq) --> AlCl3(aq) + 3 H2O(l)