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Lapatulllka [165]
3 years ago
12

How does charging by conduction occur?

Physics
1 answer:
lozanna [386]3 years ago
4 0

Hello~

The answer to your question is C.

A charged object touches a neutral object.

Explanation:

Even though it would have to be a (negative) charge, that point is that it is charge, so weather it is negative or positive, they are both charged what so ever.

~Hope this Helps!~

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Atmospheric pressure varies from day to day. The level of a floating ship on a high-pressure day is (a) higher (b) lower, or (c)
frez [133]

Answer:

(c) no different than on a low-pressure day.

Explanation:

The force acting on the ship when it floats in water is the buoyant force. According to the Archimedes' principle: The magnitude of buoyant force acting on the body of the object is equal to the volume displaced by the object.

Thus, Buoyant forces are a volume phenomenon and is determined by the volume of the fluid displaced.  

<u>Whether it is a high pressure day or a low pressure day, the level of the floating ship is unaffected because the increased or decreased pressure at the all the points of the water and the ship and there will be no change in the volume of the water displaced by the ship.</u>

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3 years ago
How much water is stored in groundwater lakes rivers soil and streams
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Answer:

Explanation:

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7 0
3 years ago
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1.what is the contour interval of this map? <br><br> 2.what is the highest elevation in this map?
alekssr [168]
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Contour interval is 50
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4 years ago
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After the car with the dead battery is running, the cables can be disconnected in the reverse order that they were connected. wh
azamat
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4 0
3 years ago
What mass of a material with density rho is required to make a hollow spherical shell having inner radius r1 and outer radius r2
Margarita [4]

Answer:

m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3  )

Explanation:

  • We have to make a hollow sphere of inner  radius r_1 and outer radius r_2.

Then the mass of the material required to make such a sphere would be calculated as:

Total volume of the spherical shell:

V_t=\frac{4}{3} \pi.r_2^3

And the volume of the hollow space in the sphere:

V_h=\frac{4}{3} \pi.r_1^3

Therefore the net volume of material required to make the sphere:

V=V_t-V_h

V=\frac{4}{3} \pi(r_2^3-r_1^3)

  • Now let the density of the of the material be \rho.

<u>Then the mass of the material used is:</u>

m=\rho.V

m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3  )

4 0
4 years ago
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