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3 years ago

How does charging by conduction occur?

Physics

1 answer:

lozanna [386]3 years ago

4 0

Hello~

The answer to your question is C.

A charged object touches a neutral object.

Explanation:

Even though it would have to be a (negative) charge, that point is that it is charge, so weather it is negative or positive, they are both charged what so ever.

~Hope this Helps!~

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Guys help me with this question.

sleet_krkn [62]

Answer:

Explanation:

Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.

1. The apparatus used are:

A is a source of light

B is a converging lens

C is a glass smoke cell

D is a microscope

2. The uses of the apparatus are:

A - produces the light required to so as to see clearly the movement of the particles.

B - converges the rays of light from the source to the smoke cell.

C - is made of glass and used for encamping the smoke particles so as not to mix with air.

D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.

4 0

3 years ago

Which statement about a flat magnet that can stick onto a refrigerator is true

zubka84 [21]

The magnetic particles are mixed with other substances to make it flexible.

7 0

3 years ago

If a client's knees hurt after a one-week walking regimen, which one of the following suggestions is most appropriate?

Flura [38]

A, it's better to take a break to let your body rejuvenate.

5 0

3 years ago

The magnitude E of an electric field depends on the radial distance r according to E = A/r4, where A is a constant with unit vol

Lesechka [4]

Answer:

$\Delta V = 0.053 A$

Explanation:

Electric field in a given region is given by equation

$E = \frac{A}{r^4}$

as we know the relation between electric field and potential difference is given as

$\Delta V = -\int E. dr$

so here we have

$\Delta V = - \int (\frac{A}{r^4}) .dr$

$\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}$

here we know that

$r_1 = 1.71 m$ and $r_2 = 2.89 m$

so we will have

$\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})$

so we will have

$\Delta V = 0.053 A$

8 0

3 years ago

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr

VladimirAG [237]

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

<u>Explanation:</u>

Given data,

E= 3 ×10 ⁶ Δx=0.06/100

We have to find the minimum potential difference

E= -ΔV/Δx

ΔV=- E × Δx

ΔV =-3 ×10 ⁶ . 0.06/100

ΔV=-1800 V

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

6 0

3 years ago