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3 years ago

An iron anchor of density 7850.00 kg/m3 appears 183 N lighter in water than in air.

Physics

1 answer:

andrew11 [14]3 years ago

3 0

<h2>a) Volume of anchor is 0.019 m³</h2><h2>b) Weight of anchor in air is 1463.17 N</h2>

Explanation:

a) Weight loss in water = Volume of object x density of water x acceleration due to gravity

183 = Volume of anchor x 1000 x 9.81

Volume of anchor = 0.019 m³

b) Weight = Mass x acceleration due to gravity = Volume x Density x acceleration due to gravity

Weight of anchor in air = Volume of anchor x Density of anchor x acceleration due to gravity

Weight of anchor in air = 0.019 x 7850 x 9.81 = 1463.17 N

Weight of anchor in air = 1463.17 N

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Solution :

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