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inn [45]
3 years ago
7

One heater uses 490 W of power when connected by itself to a battery. Another heater uses 250 W of power when connected by itsel

f to the same battery. How much total power do the heaters use when they are both connected in series across the battery?
Physics
1 answer:
insens350 [35]3 years ago
6 0

Answer:

Power will be 166.66 watt when the heater are connected in series

Explanation:

We have given power of the first heater P_1 = 490 watt

And power of the second heater P_2 = 250 watt

We know that in series connection potential difference will be same

So let the potential difference is v

Power is given by P=\frac{V^2}{R}

So 490=\frac{V^2}{R_1}

R_1=\frac{V^2}{490}=0.0020V^2

Similarly R_2=\frac{V^2}{250}=0.04V^2

As resistances are connected in series so equivalent resistance R=R_1+R_2=0.0020V^2+0.04V^2=0.006V^2

So power P=\frac{V^2}{R}=\frac{V^2}{0.006V^2}=166.66Watt

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Answer:

0 m/s

Explanation:

Velocity is displacement over time.  Displacement is the distance between your initial position and your final position.  If you walk in a circle, you end up back where you started, so your displacement is 0.  Therefore, your velocity is also 0.

8 0
3 years ago
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A wave has a wavelength of 2.30 m and a frequency of 370.0 Hz. What is the speed of the wave?
son4ous [18]

Given data:

Wave length (λ) = 2.30 m,

Frequency     (f) = 370 Hz (waves/sec),

Determine the speed of the wave = ?

Speed of the wave is defined as "the distance a wave travels in a given time". And it is a product of <em>wavelength (λ) </em>and <em>frequency(f). </em>

An Important point to be remember here is <em>"when increasing the wave length of the wave does not increase the speed of the wave"</em> because the wave speed also depends on frequency (f), So, if the wave length increases wave speed decreases. As a result the product of wave length and frequency are same.

Mathematically,

          Wave speed = wave length × frequency

                                = 2.30 m × 370 waves/sec.

                                = 851 m/s.

<em>Speed of the wave is 851 m/s</em>

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3 years ago
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After a traffic light turns green, a car is observed to accelerate from rest for 6.0 seconds. If the speed limit on that stretch
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congratulations oh feedcounsel Ozark Ozark

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3 years ago
Explain How can you<br> use a distance-time graph<br> to calculate average<br> speed?
vodomira [7]

Explanation:

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In other words, the average speed is the slope of the line connecting two points on the graph.

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3 years ago
An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.5 meters
dem82 [27]

Answer:

The electric and magnetic field are 6.34 N/C and 2.11\times10^{-8}\ T.

Explanation:

Given that,

Distance = 4.5 m

Time = 2.84 μs

We need to calculate the acceleration

Using equation of motion

The distance covered by the electron is

s=ut+\dfrac{1}{2}at^2

When, the electron at rest

s = \dfrac{1}{2}at^2

Where, s = distance

a = acceleration

t = time

Put the value into the formula

4.5=\dfrac{1}{2}\times a\times(2.84\times10^{-6})^2

a=\dfrac{2\times4.5}{(2.84\times10^{-6})^2}

a=1.116\times10^{12}\ m/s^2

We need to calculate the electric field

Using formula of the electric field

E=\dfrac{F}{q}

E=\dfrac{ma}{q}

Put the value into the formula

E=\dfrac{9.1\times10^{-31}\times1.116\times10^{12}}{1.6\times10^{-19}}

E=6.34\ N/C

We need to calculate the magnetic field

Using formula of magnetic field

B = \dfrac{E}{c}

Put the value into the formula

B=\dfrac{6.34}{3\times10^{8}}

B=2.11\times10^{-8}\ T

According to the right hand rule,

The direction of magnetic field is outward because the direction of force is upward.

Hence, The electric and magnetic field are 6.34 N/C and 2.11\times10^{-8}\ T.

8 0
3 years ago
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