Ask question

Ask question

All categories

3 years ago

13

True or False

2 answers:

daser333 [38]3 years ago

8 0

Answer:

if its both opposite symbols, they will attract, if they are the same symbols, they will repel

Explanation:

Hope it helps ( :

(P.S. there's no pic)

Softa [21]3 years ago

7 0

Answer:

True

Explanation:

You might be interested in

Which of the following elements has a complete outer shell of electrons? A. Iron (Fe) B. Hydrogen (H) C. Neon (Ne) D. Nitrogen (

Julli [10]

Answer:

The answer is Neon

3 0

3 years ago

What is my theoretical yield (in moles) of Potassium Bromide (KBr) if I start with 40 grams of Iron (II) Bromide [FeBr2]? moles

Verizon [17]

The reaction will be: FeBr2 + K --> KBr + Fe
Balancing gives: FeBr2 + 2K --> 2KBr + Fe
The molar mass of FeBr2 is 55.85 + 2*79.9 = 215.65 g/mol.
We divide 40 g / 215.65 g/mol = 0.185 mol FeBr2
Based on stoichiometry:
(0.185 mol FeBr2)(2 mol KBr/1 mol FeBr2) = 0.370 mol KBr

4 0

4 years ago

Which battle led to the mass displacement of Cherokee from their homes?

zzz [600]

Answer:

option d.......................

3 0

3 years ago

Read 2 more answers

A gas is collected at 20.0 °C and 725.0 mm Hg. When the temperature is

krek1111 [17]

Answer:

676mmHg

Explanation:

Using the formula;

P1/T1 = P2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 725.0mmHg

P2 = ?

T1 = 20°C = 20 + 273 = 293K

T2 = 0°C = 0 + 273 = 273K

Using P1/T1 = P2/T2

725/293 = P2/273

Cross multiply

725 × 273 = 293 × P2

197925 = 293P2

P2 = 197925 ÷ 293

P2 = 676mmHg.

The resulting pressure is 676mmHg

3 0

3 years ago

A first-order reaction has a half-life of 29.8 s . How long does it take for the concentration of the reactant in the reaction t

lutik1710 [3]

Answer : The time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

Explanation :

Half-life = 29.8 s

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{29.8s}$

$k=0.0232s^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $0.0232s^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = x M

a - x = amount left after decay process = $x-\frac{1}{4}\times (x)=\frac{3}{4}\times (X)=\frac{3x}{4}M$

Now put all the given values in above equation, we get

$t=\frac{2.303}{0.0232s^{-1}}\log\frac{x}{(\frac{3x}{4})}$

$t=12.4s$

Therefore, the time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

7 0

4 years ago