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MissTica
3 years ago
6

What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
6 0

Answer:

= C3H4N

Explanation:

We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

We first calculate the number of moles of each element.

Carbon = 90g/12 g/mol

            = 7.5 moles

Hydrogen = 11 g/ 1 g/mol

                 = 11 moles

Nitrogen = 35 g/ 14 g/mol

               = 2.5 moles

The we get the mole ratio of the elements;

= 7.5/2.5 : 11/2.5 : 2.5 /2.5

= 3 : 4.4 : 1

= 3 : 4 : 1

Therefore;

The empirical formula will be; C3H4N

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How many grams of solute are needed to order to prepare 100.00 mL of a 0.1000 M solution of a compound with a molecular weight o
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The grams of solute are required.

The mass of solute is 3.5 g

c =  Molarity = 0.1 M

M = Molar mass = 350 g/mol

V = Volume of solution = 100 mL = 0.1 L

n = Number of moles

m = Mass of solute

Molarity is given by

c=\dfrac{n}{V}\\\Rightarrow n=cV\\\Rightarrow n=0.1\times 0.1\\\Rightarrow n=0.01\ \text{moles}

Molar mass is given by

M=\dfrac{m}{n}\\\Rightarrow m=Mn\\\Rightarrow m=350\times 0.01\\\Rightarrow m=3.5\ \text{g}

The mass of solute is 3.5 g

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Find the density of a gas at STP if it’s molar mass is 112g/mol
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