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faltersainse [42]
3 years ago
12

Tidal power can be generated by man without investing a lot of energy into the process. True False

Physics
2 answers:
tiny-mole [99]3 years ago
6 0

Answer: True

Explanation: Tidal Power can be generated with with less efforts and investment. The tidal energy is generated by the help of the tidal energy generators.

These generators are fitted in underwater turbines which has high tidal movements, which are designed to capture the kinetic motion of the surging of ocean in order to produce electricity.

Dmitriy789 [7]3 years ago
4 0

If only that were true, you would see tidal power stations
all up and down every coast by now.

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Ron fills a beaker with glycerin (n = 1.473) to a depth of 5.0 cm. if he looks straight down through the glycerin surface, he wi
Tju [1.3M]

By law of refraction we know that image position and object positions are related to each other by following relation

\frac{\mu_1}{h_o} = \frac{\mu_2}{h_i}

here we know that

\mu_1 = 1.473

h_o = 5 cm

\mu_2 = 1

now by above formula

\frac{1.473}{5} = \frac{1}{h_i}

h_i = 3.39 cm

so apparent depth of the bottom is seen by the observer as h = 3.39 cm

7 0
3 years ago
If a system has 475 kcal of work done to it, and releases 5.00 × 102 kJ of heat into its surroundings, what is the change in int
Andrews [41]
First, we convert kcal to joules:
1 kcal = 4.184 kJ
475 kcal = 1987.4 kJ

Now, calculating the change in internal energy:

ΔU = Q + W; where Q is the heat supplied to the system and W is the work done on the system.

ΔU = -500 + 1987.4
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4 0
3 years ago
Read 2 more answers
In a shipping company distribution center, an open cart of mass 50.0 kg is rolling to the left at a speed of 5.00 m/s. Ignore fr
spin [16.1K]

Answer:

a) v_p=9.35m/s

Explanation:

From the question we are told that:

Open cart of mass   M_o=50.0 kg

Speed of cart   V=5.00m/s

Mass of package   M_p=15.0kg

Speed of package at end of chute V_c=3.00m/s

Angle of inclination   \angle =37

Distance of chute from bottom of cart   d_x=4.00m

a)

Generally the equation for work energy theory is mathematically given by

  \frac{1}{2}mu^2+mgh=\frac{1}{2}mv_p^2

Therefore

  \frac{1}{2}u^2+gh=\frac{1}{2}v_p^2

  v_p=\sqrt{2(\frac{1}{2}u^2+gh)}

  v_p=\sqrt{2(\frac{1}{2}v_c^2+gd_x)}

  v_p=\sqrt{2(\frac{1}{2}(3)^2+(9.8)(4))}

  v_p=9.35m/s

4 0
2 years ago
In the diagram, the trough of the wave is shown by:
Kisachek [45]

Answer:

the correct representation of the trough is b

3 0
3 years ago
Calculate the mechanical advantage of a hammer, if the input force is 125 N
olganol [36]

Answer:

16

Explanation:

Mechanical advantage = force out / force in

MA = 2000 N / 125 N

MA = 16

5 0
3 years ago
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