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3 years ago

Tidal power can be generated by man without investing a lot of energy into the process. True False

Physics

2 answers:

tiny-mole [99]3 years ago

6 0

Answer: True

Explanation: Tidal Power can be generated with with less efforts and investment. The tidal energy is generated by the help of the tidal energy generators.

These generators are fitted in underwater turbines which has high tidal movements, which are designed to capture the kinetic motion of the surging of ocean in order to produce electricity.

Dmitriy789 [7]3 years ago

4 0

If only that were true, you would see tidal power stations
all up and down every coast by now.

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Speedy Sue, driving at 34.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 160 m ahead traveling at 5.40 m/s

emmasim [6.3K]

Answer:

Yes, there will be collision.

Explanation

Initial relative velocity u = 34-5.4 = 28.6 m/s

required final relative velocity v = 0

Acceleration , suppose be a .

Distance traveled =d = 160 m

Using the formula for relative motion,

v² - u² = 2as

0 - 28.6²=2as

a = - 2.55 m s⁻².

Since this required value is more than maximum braking deceleration so , there will be collision.

5 0

3 years ago

Read 2 more answers

What is a device that transforms thermal energy to mechanical energy

Ainat [17]

I think that's <span>heat engine.</span>

I hope I helped :D

6 0

3 years ago

An object with a mass of 2 kg is acted upon by a force of 8 N. What is the resulting acceleration of the object?

Tomtit [17]

Answer:

4 meter per second square is the acceleration

Explanation:

Force=mass x acceleration

8N= 2kg x acceleration

8N/2kg = acceleration

4 meter per second square is the acceleration.

<em>Please mark me as brainliest.</em>

4 0

3 years ago

A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062

galina1969 [7]

Answer:

Force on the proton will be $.73\times 10^{-14}N$

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light $c=3\times 10^8m/sec$

So speed of proton $v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec$

Magnetic field B = 0.00629 T

Charge on proton $q=1.6\times 10^{-16}C$

Angle between velocity and magnetic field $\Theta =137^{\circ}$

Force on the proton is equal to $F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N$

4 0

3 years ago

Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay

Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, $m_1=0.205\ kg$

Speed of the model, $u_1=0.72\ m/s$

Mass of another model, $m_2=0.32\ kg$

Initial speed of another model, $u_2=0$

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

$m_1u_1+m_2u_2=(m_1+m_2)V$

$V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}$

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0

3 years ago