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Reika [66]
3 years ago
12

The molecule mass of sodium oxide na2o is

Chemistry
2 answers:
garri49 [273]3 years ago
8 0
Molecular mass of Na2O = 46+16= <span>62 u</span>
maxonik [38]3 years ago
7 0
it is 61.97894 g/mol
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C2H2 + 2H2 → C2H6<br> How many moles of hydrogen are needed to produce 13.78 mol of ethane?
Scilla [17]

Answer:

27.56 moles

Explanation:

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4 years ago
Equilin is an estrogen isolated from the urine of pregnant mares. The percent composition of equilin is 80.56 percent C, 7.51 pe
tatuchka [14]

Answer:

The correct answer is C18H20O2.

Explanation:

Based on the given information, one hundred grams of equilin contains 80.56% Carbon, 7.51% Hydrogen, and 11.95% Oxygen. Thus, by mass it comprises 80.56 g Carbon, 7.51 g Hydrogen, and 11.92 g Oxygen.

The molecular mass of carbon, hydrogen, and oxygen are 12.01 g/mol, 1.008 g/mol, and 16.00 g/mol.

The moles of the elements present can be determined by using the formula,

Moles = Weight/Molecular mass

Moles of C = 80.56 g/12.01 g/mol = 6.708 mol

Moles of H = 7.51 g/1.008 g/mol = 7.45 mol

Moles of O = 11.92 g/16 g/mol = 0.745 mol

This gives the formula of C6.708H7.45O0.745. By dividing the subscripts from the smallest value, the possible whole numbers obtained will be,

6.708/0.745 = 9, 7.45/0.745 = 10, 0.745/0.745 = 1. Now the empirical formula obtained will be, C9H10O

Now dividing the molar mass of equilin, that is, 268 g/mol from the empirical formula mass, that is, 9*12.01 g/mol + 10*1.008 g/mol+ 16.00 g/mol = 134.2 g/mol, we get,

268/134.2 = 2

Now by multiplying the subscripts in the empirical formula with 2, the molecular formula obtained will be,

C18H20O2.

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3 years ago
Do you know that Jesus Loves you ? If you dont know now that he does and always has and you've always had God' Grace ​
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Read 2 more answers
An igneous rock originally has 3 grams of uranium 238 in it. When dated the rock only contains 1.8 grams. What are the parent an
castortr0y [4]

Answer :

The parent and daughter concentrations (in percentages) is, 60 % and 40 % respectively.

The age of rock is 3.32\times 10^9\text{ years}

Explanation :

First we have to calculate the parent and daughter concentrations (in percentages).

\text{Parent concentrations}=\frac{1.8g}{3g}\times 100=60\%

and,

\text{Daughter concentrations}=\frac{(3-1.8)g}{3g}\times 100=40\%

As we know that, the half-life of uranium-238 = 4.5\times 10^9 years

Now we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{4.5\times 10^9\text{ years}}

k=1.54\times 10^{-10}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.54\times 10^{-10}\text{ years}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant  = 3 g

a - x = amount left after decay process = 1.8 g

Now put all the given values in above equation, we get

t=\frac{2.303}{1.54\times 10^{-10}}\log\frac{3}{1.8}

t=3.32\times 10^9\text{ years}

Therefore, the age of rock is 3.32\times 10^9\text{ years}

5 0
3 years ago
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