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vesna_86 [32]
3 years ago
10

While exploring a coal mine, scientists found plant fossils in the ceiling of the mine which had been preserved by an earthquake

. Samples taken from one of the fossils have carbon‑14 activities of 40.0 counts/min. A reference sample of the same size, from a plant alive today, has a carbon‑14 activity of 160.0 counts/min.
If carbon‑14 has a half‑life of 5730 years, what is the age of the plant fossil in years?
Chemistry
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

11552.45 years

Explanation:

Given that:

Half life = 5730 years

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{5730}\ years^{-1}

The rate constant, k = 0.00012 years⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.00012 years⁻¹

Initial concentration [A_0] = 160.0 counts/min

Final concentration [A_t] = 40.0 counts/min

Time = ?

Applying in the above equation, we get that:-

40.0=160.0e^{-0.00012\times t}

e^{-0.00012t}=\frac{1}{4}

-0.00012t=\ln \left(\frac{1}{4}\right)

t=11552.45\ years

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