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Kobotan [32]
4 years ago
5

30 points for 3 questions. The answer with all correct will get brainliest! PLEASE HELP!

Chemistry
2 answers:
Natasha_Volkova [10]4 years ago
7 0
1. "B. It is physically combined." Vinegar is not a naturally occurring substance. 

2."A. solute; solvent" This is because they are both pure elements in this scenario, if they were not the answer would be C

3."<span>B. 50 g</span>" the sugar has dissolved and become a part of the mixture the sugar does not affect the weight b=due to the dissolving. 



Sunny_sXe [5.5K]4 years ago
7 0
For #1 A) its a pure substance

#2 B)

#3 im not sure about this but B
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A solution of starch at room temperature does not readily decompose to form a solution of simple sugars because
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Explanation:

The starch requires a temperature higher than the room temperature (arround 60 °C) to decompose to form simple sugars. This is because the energy required to break the chemical bonds. Also, it may need the action of some specific enzymes (alpha and beta amilase) to break those bonds.

6 0
3 years ago
When a 0.245-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.260-g sample
sveticcg [70]

Answer:

The heat of combustion per moles of caffeine is 4220 kJ/mol

Explanation:

Step 1: Data given

⇒ When  benzoic acid sample of 0.245 grams is burned the temperature rise is 1.643 °C

⇒ When 0.260 gram of caffeine is burned, the temperature rise is 1.436 °C

⇒ Heat of combustion of benzoic acid = 26.38 kJ/g

<u>Step 2:</u> Calculate the heat released: for combustion of benzoic acid

0.245 g benzoic acid *  26.38 kJ/g = 6.4631 kJ

<u>Step 3</u>: Calculate the heat capacity of the calorimeter:

c = Q/ΔT

Q = 6.4631 kJ   / 1.643°C = 3.934 kJ/ °C

<u>Step 4:</u> Calculate moles of a 0.260 g sample of caffeine:

Moles caffeine = Mass caffeine / Molar mass caffeine

0.260 grams/ 194.19 g/mol  = 0.0013389 moles

Step 5: Calculate heat released: for combustion of caffeine

Q = c * ΔT

Q = 3.934 kJ/°C * 1.436 °C = 5.65 kJ

Step 6: Calculate the heat of combustion per mole of caffeine  

5.65 kJ  /  0.0013389 moles = 4219.9 kJ/mol  ≈ 4220 kJ/mol

The heat of combustion per moles of caffeine is 4220 kJ/mol

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