Option (c) is correct.
Explanation:
initial velocity along vertical=0
velocity along horizontal Vx=40.20 m/s
acceleration along the vertical=9.8 m/s²
displacement along vertical,h=2 m
using the kinematic equation
h= vi*t + 1/2 g t²
2=0(t) + 1/2 (9.8)t²
t²=0.408
t=0.639 s
now the displacement along vertical= x= Vx* t
x=40.20 (0.639)
x=25.73 m
Answer:
-8.04 m/s2
Explanation:
To find the answer to this, you have to use the 4th kinematic equation:
You plug into the equation to get:
solve for a to get
-8.04 m/s2
Kinetic energy = 1/2 (mass)*(velocity)^2
ke = 1/2 (1500kg) (17m/s)^2
ke = 216750 kg*m^2/s^2 = 216750 Joules
(sorry, I don't know significant figures. but this is otherwise the correct answer with the right units. hope this helps!! :))
Hello, I see you are in a jam. Lemme help.
1.) True
2.) True
3.) True
4.) True
5.) True
LOL these are all true ;)
