Answer:
Explanation:
-The chemical formula for Molybdenum (V) Dichromate is
-There are 21 moles of oxygen per one mole of Molybdenum (V) Dichromate
-We apply Avogadro's constant to find the number of atoms of oxygen:
Hence, there are
Describe and name the different types of collision. In which are the linear momentum and kinetic energy conserved
1 answer:
Answer:
1. Elastic collision
2. Inelastic collision
Explanation:
Elastic collision: collision is said to be elastic if total kinetic energy is not conserved and if there is a rebound after collision
the collision is described by the equation bellow
Inelastic collision: this type of collision occurs when the total kinetic energy of a body is conserved or when the bodies sticks together and move with a common velocity
the collision is described by the equation bellow
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Answer:
52 mm/s (approximately)
Explanation:
Given:
Initial speed of the projectile is,
Angle of projection is,
Time taken to land on the hill is,
In a projectile motion, there is acceleration only in the vertical direction which is equal to acceleration due to gravity acting vertically downward. There is no acceleration in the horizontal direction.
So, the velocity in the horizontal direction always remains the same.
The horizontal component of initial velocity is given as:
Now, the velocity in the vertical direction goes on decreasing and becomes 0 at the highest point of the trajectory. So, at the highest point, only horizontal component acts.
Therefore, the projectile's velocity at the highest point of its trajectory is equal to the horizontal component of initial velocity and thus is equal to 52 mm/s.
Specific heat of the material thus calculated is 0.22 J/ g °C
<u>Explanation</u>:
Given:
Mass of the sample (m) = 50g
Heat energy = Q = 660 J
Temperature get raised from 20° C to 80° C
To Find:
Specific Heat of the material.
Formula to be used:
Q = m×C×ΔT
where we know that,
Heat energy = Q = 660 J
Mass = m = 50 g
ΔT = 80 - 20 = 60° C
Now to calculate the specific heat of the material (c) we must substitute all the values, Then we get,
Thus the Specific heat of the material is 0.22 J/ g °C.