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denis-greek [22]
3 years ago
6

During reduction, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g

ained, so the oxidation number decreases. C. Electrons are given off, so the oxidation number increases. D. Electrons are given off, so the oxidation number decreases.
Chemistry
1 answer:
Pani-rosa [81]3 years ago
6 0

Answer:

B. Electrons are gained, so the oxidation number decreases.

Explanation:

Reduction is the <em>gain of electrons</em>.

Oxidation number is the charge that an atom <em>appears</em> to have when we count its electrons in a specific way.

Electrons have a negative charge so, if an atom gains electrons, its charge (oxidation number) becomes more negative. The oxidation number decreases.

If electrons are given off, the atom is being oxidized. Loss of electrons is <em>oxidation</em>.

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8moles of Na2Cr2O2 is how much mass​
Margaret [11]

\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }

\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of Na_2Cr_2O_2 weighs = 182 g

8 moles weigh = 8× 182

=\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}

or

\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}

5 0
2 years ago
What is the molarity of a solution containing 8.9 g of NaOH in 550. mL of NaOH solution?
bulgar [2K]

Answer:

0.4 M

Explanation:

Molarity is defined as moles of solute, which in your case is sodium hydroxide,  

NaOH

, divided by liters of solution.

molarity

=

moles of solute

liters of solution

Notice that the problem provides you with the volume of the solution, but that the volume is expressed in milliliters,  

mL

.

Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to

determine how many moles of sodium hydroxide you have in that many grams

convert the volume of the solution from milliliters to liters

So, to get the number of moles of solute, use sodium hydroxide's molar mass, which tells you what the mass of one mole of sodium hydroxide is.

7

g

⋅

1 mole NaOH

40.0

g

=

0.175 moles NaOH

The volume of the solution in liters will be

500

mL

⋅

1 L

1000

mL

=

0.5 L

Therefore, the molarity of the solution will be

c

=

n

V

c

=

0.175 moles

0.5 L

=

0.35 M

Rounded to one sig fig, the answer will be

c

=

0.4 M

Explanation:

6 0
2 years ago
Please help me outttt
leonid [27]

Answer:

4.) 9, 1, and 4    5.) 4, 1, and 4

Explanation:

I am not quite sure about this because I cannot remember if the coefficient (the number before the elements) is applied to every element in the compound. If it is then your number of atoms are as follows: CORRECTION: you do not have to apply the coefficient to every element only the one that is after it. So when you back and fix the error your number of atoms will be as follows:

number 4

H: 9

P: 1

O: 4

number 5:

H: 4

S: 1

O: 4

you can calculate the number of atoms present in this compound by multiplying the coefficient and the subscripts of each atom.

hope this helped you :)

7 0
2 years ago
For each value of the principal quantum number n, what are the possible values of the electron spin quantum number?
Ede4ka [16]

Answer:

The values for spin quantum number +1/2 and - 1/2

Explanation:

Principal quantum number denoted by (n) is used to describe the shell or orbits that electrons are found. Principal quantum number can assume a value of n= 1,2, 3, 4,5............ which indicates K, L, M, N, O shell respectively.

To know the maximum number of electrons in each shell, the formula (2n²) can be used. The letter 'n' denotes the values of principal quantum number 1,2,3,4

For example

  • n=1 (K shell) has maximum number of 2 electrons
  • n=2 (L shell) has the maximum number of 8 electrons
  • n=3 (M shell) has the maximum number of 18 electrons
  • n=4 (N shell) has the maximum number of 32 electrons

All the electron in each shell will have a spin quantum number of +1/2 and - 1/2. One electron in each degenerate orbital will spin up (+1/2) while the other electron will spin down (-1/2).

7 0
3 years ago
hich of the followings decrease the affinity of adult Hb with O2? A. 2,3 BPG B. hydrogen ion C. CO2 D. Ferrous ion
Ivahew [28]

Answer:

A. 2,3 BPG

Explanation:

2,3-bisphosphoglycerate (BPG), otherwise known as 2,3-DPG, enables the transition of hemoglobin from a very high-oxygen-affinity state to a reduced-oxygen-affinity state.

Tissues hemoglobin oxygen affinity is reduced by numerous physiological factors including.

1. Temperature Increased,

2. Carbon dioxide,

3. Acid and

4. 2,3-Bisphosphoglycerate (2,3-BPG)

all of which can contribute to decrease the oxygen affinity of hemoglobin which favours unloading and increased oxygen availability to our body cells.

3 0
2 years ago
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