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denis-greek [22]
3 years ago
6

During reduction, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g

ained, so the oxidation number decreases. C. Electrons are given off, so the oxidation number increases. D. Electrons are given off, so the oxidation number decreases.
Chemistry
1 answer:
Pani-rosa [81]3 years ago
6 0

Answer:

B. Electrons are gained, so the oxidation number decreases.

Explanation:

Reduction is the <em>gain of electrons</em>.

Oxidation number is the charge that an atom <em>appears</em> to have when we count its electrons in a specific way.

Electrons have a negative charge so, if an atom gains electrons, its charge (oxidation number) becomes more negative. The oxidation number decreases.

If electrons are given off, the atom is being oxidized. Loss of electrons is <em>oxidation</em>.

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JulijaS [17]
Answer:
mass of HCl = 243.5426 grams

Explanation:
1- we will get the mass of the reacting gold:
volume of gold = length * width * height
volume of gold = 3.2 * 3.8 * 2.8 = 34.048 cm^3 = 34.048 ml<span>
density = mass / volume
Therefore:
mass = density * volume
mass of gold = </span>19.3 * 34.048 = 657.1264 grams

2- we will get the number of moles of the reacting gold:
number of moles = mass / molar mass
number of moles = 657.1264 / 196.96657 
number of moles = 3.3362 moles

3- we will get the number of moles of the HCl:
First, we will balanced the given equation. The balanced equation will be as follows:
Au + 2HCl ......> AuCl2 + H2
This means that one mole of Au reacts with 2 moles of HCl.
Therefore 3.3362 moles will react with 2*3.3362 = 6.6724 moles of HCL

4- we will get the mass of the HCl:
From the periodic table:
molar mass of H = 1 gram
molar mass of Cl = 35.5 grams
Therefore:
molar mass of HCl = 1 + 35.5 = 36.5 grams/mole
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass of HCl = 6.6724 * 36.5
mass of HCl = 243.5426 grams

Hope this helps :)
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Why did bohrs observations of gaseous elements not reveal a complete spectrum when the light was shone through a prism? explain
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Answer:

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What is the mass of solute in a 500 mL solution of 0.200 M
Fofino [41]

16.4 grams is the mass of solute in a 500 mL solution of 0.200 M .

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Explanation:

Given data about sodium phosphate

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volume of the solution = 500 ml or 0.5 litres

molarity of sodium phosphate solution = 0.200 M

The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:

The formula is

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molarity x volume = number of moles

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164 x 0.1 = 16.4 grams

16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.

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