In which direction would a positive charge move if it were placed in between the positive and negative charge

Mutations are avoided during replication because DNA polymerase is able to _____?

Ulleksa [173]

D. add more codes
hope this helped

3 0

3 years ago

The secondary coil of a neon sign transformer provides 7500 V at 0.01 A. The primary coil operates on 120 V. What is the input c

nikitadnepr [17]

Answer:

0.625 A

Explanation:

Vs = 7500 V, Is = 0.01 A

Vp = 120 V

Let the primary current be Ip.

As the transformer is ideal, so input power is equal to the output power

Vp x Ip = Vs x Is

120 x Ip = 7500 x 0.01

Ip = 0.625 A

8 0

3 years ago

Adjacent antinodes of a standing wave on a string are 15.0 cmapart. A particle at an antinode oscillates in simpleharmonic motio

viva [34]

Answer:

a) D = 15 cm , b) λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e) v = 80.43 cm / s , v = -80.43 cm / s, f) D₂= 7.5 cm

Explanation:

Standing waves form when two waves of the same frequency travel in opposite directions,

A) in the waves the distance of the nodes and antinode are the same since the wavelength is constant

D = 15 cm

B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is lamita of the wavelength.

D = λ / 2

λ= 15 2

λ = 30.0 cm

C) the amplitude of each wave is 0.0850 cm, the amplitude of the standing wave is double A = 0.17 cm

D) Let's use the speed ratio

v = λ f

f = 1 / T

v = λ / T

v = 30.0 /0.0750

v = 400 cm / s

E) the transverse speeds are the speed of the oscillatory movement

y = A cos (wt)

w = 2π f = 2π / T

w = 2π / 0.0750

w = 83.78 rad / s

y = 0.850 cos (83.78 t)

Speed is

v = dy / dt

v = -A w cost wt

v = - 0.850 83.78 cos (83.78 t)

v = -80.43 cos (83.78 t)

The maximum speed when the cosine values ±1

v = 80.43 cm / s

v = -80.43 cm / s

F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength

D₂ = ¼ λ

D₂ = 30.0/4

D₂= 7.5 cm

5 0

3 years ago

A block is at rest on the incline shown in the figure. The coefficients of static and ki- netic friction are μs = 0.62 and μk =

GREYUIT [131]

The frictional force is 218.6 N

Explanation:

The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.

There are two forces acting along this direction:

- The component of the weight parallel to the incline, downward along the plane, of magnitude

$mg sin \theta$