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NeTakaya
3 years ago
15

In which direction would a positive charge move if it were placed in between the positive and negative charge

Physics
1 answer:
Airida [17]3 years ago
8 0

Answer:

I think it would move right

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What is a charge-coupled device (CCD), and how is it used in astronomy?
Sedaia [141]

Answer:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region

Explanation:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region where it can be modified like changing it to a electronic value.

In astronomy, high-powered telescopes can be used with CCD device image sensor cameras. The imaging system can concentrate for a number of hours on one place in space once the Earth's rotation synchronizes with the telescope.

6 0
4 years ago
A machine does 500 j of work in 20 sec. What is the power of this machine?
NNADVOKAT [17]

Explanation:

P=W/t

P=500/20

P=25 W

6 0
3 years ago
The difference in the composition of the terrestrial planets and the gas giants can be explained by the different condensation
miv72 [106K]
The inner planets are usually rocky because the gravitational pull is stronger closer to the star or in this case the sun. The dust and rocky particles that are left over after a super nova or in a nebula will tend to orbit closer to a proto-star when a solar system is in its early days. In our solar system these planets are Mercury, Venus, Earth and Mars. Gases are less dense and will be less affected by the pull of gravity because rocky particles have more mass. The outer planets are gas giants formed from clouds of gas that would be further out in the spinning disk around a proto-star. 
6 0
4 years ago
A ball is dropped , find the velocity after 100 m
Marat540 [252]

Answer:

Vf = 44.27 m/s

Explanation:

When a ball is dropped it is acted upon by gravitational force under free fall motion. So, in order to find its final speed we use 2rd equation of motion, as follows:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height lost = 100 m

Vf = Final Velocity = ?

Vi = Initial velocity = 0 m/s (Since, ball starts from rest)

Therefore,

(2)(9.8 m/s²)(100 m) = Vf² - (0 m/s)²

Vf = √(1960 m²/s²)

<u>Vf = 44.27 m/s</u>

5 0
3 years ago
If a box is pushed across a floor with a force of 130N. The frictional force acting between the box and the floor is 30N, over a
Sidana [21]
The force acting in the front direction is the 130N.
The frictional force is acting backwards          30N.

1) The net force is 130N - 30N    =  100N

2)  s  = ut + (1/2)at^2             u = 0,  Start from rest,  s = 25m t =5.

25 = 0*5  +  (1/2)* a * 5^2.

25 = 0  +  25/2  * a.

25  =    (25/2)a.      Divide 25 from both sides.

1 =  (1/2)* a.          Cross multiply.

2 = a.

a = 2 m/s^2.

3) Mass of the box
Net Force,  F = ma
                   100 =  m*2.        Divide both sides by 2.
                    
                     100/2  =  m
                       50       =  m.
                        m  = 50 kg.

4)  Final velocity ,   v = u + at.
                                   v  =  0  + 2*5 = 10 m/s.
                                  
   Kinetic Energy,  K  =  (1/2) * mv^2.
                                    =    1/2  * 50 * 10 * 10.
                                    =      2500 J.
3 0
3 years ago
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