Answer:
95.9°
Explanation:
The diagram illustrating the action of the two forces on the object is given in the attached photo.
Using sine rule a/SineA = b/SineB, we can obtain the value of B° as shown in the attached photo as follow:
a/SineA = b/SineB,
83/Sine52 = 56/SineB
Cross multiply to express in linear form
83 x SineB = 56 x Sine52
Divide both side by 83
SineB = (56 x Sine52)/83
SineB = 0.5317
B = Sine^-1(0.5317)
B = 32.1°
Now, we can obtain the angle θ, between the two forces as shown in the attached photo as follow:
52° + B° + θ = 180° ( sum of angles in a triangle)
52° + 32.1° + θ = 180°
Collect like terms
θ = 180° - 52° - 32.1°
θ = 95.9°
Therefore, the angle between the two forces is 95.9°
Answer:
Dimension of cardboard is 22 m by 16 m
Explanation:
Given that,
Area = 352 cm²
Side of each square cutting from corner = 2 cm
Volume of box = 432 cm³
Let the two sides are x and y.
The area of the rectangular piece is
-------- (1)
The volume of the rectangular piece
x=16,22
Put the value of x in the equation (I)
For x = 16
For x = 22
Dimension of cardboard is 22 m by 16 m