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MA_775_DIABLO [31]
3 years ago
5

What is the volume, in liters, of 1.40 mol of oxygen gas at 20.0°C and 0.974 atm?

Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

V = 34.55 L

Explanation:

Given that,

No of moles, n = 1.4

Temperature, T = 20°C = 20 + 273 = 293 K

Pressure, P = 0.974 atm

We need to find the volume of the gas. It can be calculated using Ideal gas equation which is :

PV=nRT

R is gas constant, R=0.08206\ L-atm/mol-K

Finding for V,

V=\dfrac{nRT}{P}\\\\V=\dfrac{1.4\times 0.08206\times 293}{0.974 }\\\\V=34.55\ L

So, the volume of the gas is 34.55 L.

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When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40
slava [35]
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

  =heat  capacity of  bomb  calorimeter x  delta  T  where  delta T   is  change   in temperature
delta T  = 29.4  -25.8= 3.6 c

= 5.86 kj/c   x  3.6 c =  21.096  kj


7 0
3 years ago
How to answer all these questions?
Fudgin [204]
You have to do it to see the results
8 0
3 years ago
Does anyone know how to do this?
Sloan [31]

Answer

find out the number of moles and use the molar ratio (numbers in front of formulas (in this case they are all 1) to determine how many moles of each product you are going to get theoretically

n=m/M is the equation to use to get moles here

30.8 gm/32.04 g/mol=0.9612 moles of the methanol and also of the formaldehyde so

0.9612 moles of the formaldehyde x molar mass (M) 30.73 g/mol= 29.54 gm which is the theoretical yield you already have the actual yield of 24.7 gm

then divide the actual by the theoretical to get the % yield which is 83.6%

Explanation:

4 0
3 years ago
When a candle burns what form of energy does the chemical energy in the candle change
soldier1979 [14.2K]
The energy transforms from chemical energy to heat and light energy. Because when the candle burns a chemical reaction occurs, and produces heat and light.
8 0
3 years ago
An aqueous solution is found to be 3.64% potassium nitrate by mass, how many grams of solution should I evaporate the water from
Sidana [21]

Answer:

513.74 g of solution

Explanation:

% Mass grams are defined as the <em>grams that are dissolved in salt</em> (in this case, it would be <em>potassium nitrate</em>) <em>dissolved every 100 g of the solution</em>. Having this information, you can calculate the amount of solution that has dissolved 18.7 g of potassium nitrate, which is what we want to obtain.

The relationship is:

3.64 g of potassium nitrate _____ 100 g solution

18.7 g of potassium nitrate _____ X = 513.74 g of solution

Calculation: 18.7g x 100g / 3.64g = 513.74 g of solution

So, <em>I need 513.74 g of solution to get 18.7g of potassium nitrate by evaporating it</em>.

8 0
3 years ago
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