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MA_775_DIABLO [31]
3 years ago
5

What is the volume, in liters, of 1.40 mol of oxygen gas at 20.0°C and 0.974 atm?

Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

V = 34.55 L

Explanation:

Given that,

No of moles, n = 1.4

Temperature, T = 20°C = 20 + 273 = 293 K

Pressure, P = 0.974 atm

We need to find the volume of the gas. It can be calculated using Ideal gas equation which is :

PV=nRT

R is gas constant, R=0.08206\ L-atm/mol-K

Finding for V,

V=\dfrac{nRT}{P}\\\\V=\dfrac{1.4\times 0.08206\times 293}{0.974 }\\\\V=34.55\ L

So, the volume of the gas is 34.55 L.

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PLEASE HELP ASAP!! {40 POINTS}
yan [13]

Answer:

The correct answer is -

FALSIFIABLE:

Aloe vera gel can heal wounds by boosting cell renewal.

Drinking aloe juice can reduce the risk of lung cancer.

NON-FALSIFIABLE:

Aloe vera gel is the best natural skin moisturizer.

Aloe vera juice tastes better than carrot juice.

Explanation:

Falsifiable is the ability or chances of any hypothesis, claim or statement to be proved wrong. In such a hypothesis, it is possible to carry an experimental observation that disproves the idea in claim or question.

In the given examples

Aloe vera gel can heal wounds by boosting cell renewal.

Drinking aloe juice can reduce the risk of lung cancer.

There is no observation in the favor of the claim so there more likely to be falsifiable whereas, Aloe vera gel is the best natural skin moisturizer.

Aloe vera juice tastes better than carrot juice are more non-falsifiable as these are based on personal choice or experimental observation.

7 0
3 years ago
A 2.0 L container of nitrogen gas had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1.0 atm
beks73 [17]

Answer:

6.4 L

Explanation:

When all other variables are held constant, you can use Boyle's Law to find the missing volume:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.

P₁ = 3.2 atm                      P₂ = 1.0 atm

V₁ = 2.0 L                          V₂ = ? L

P₁V₁ = P₂V₂                                                    <----- Boyle's Law

(3.2 atm)(2.0 L) = (1.0 atm)V₂                        <----- Insert values

6.4 = (1.0 atm)V₂                                           <----- Simplify left side

6.4 = V₂                                                        <----- Divide both sides by 1.0

6 0
2 years ago
Look at the image below. What is the ratio of the formula shown? *
aleksklad [387]
It’s 1:1 b3cuae that’s the one u can
6 0
3 years ago
Read 2 more answers
How does Fluoroanimonic acid melt things?
Tomtit [17]

Answer:s the temperature is increased, fluoroantimonic acid decomposes and generates hydrogen fluoride gas (hydrofluoric acid). ... 1  Fluoroantimonic acid has a H0 (Hammett acidity function) value of -31.3. Dissolves glass and many other materials and protonates nearly all organic compounds (such as everything in your body)

tall me is this what you looking for

4 0
3 years ago
If 4.0 g of helium gas occupies a volume of 22.4 L at 0 o C and a pressure of 1.0 atm, what volume does 3.0 g of He occupy under
WINSTONCH [101]

Answer:

the volume occupied by 3.0 g of the gas is 16.8 L.

Explanation:

Given;

initial reacting mass of the helium gas, m₁ = 4.0 g

volume occupied by the helium gas, V = 22.4 L

pressure of the gas, P = 1 .0 atm

temperature of the gas, T = 0⁰C = 273 K

atomic mass of helium gas, M = 4.0 g/mol

initial number of moles of the gas is calculated as follows;

n_1 = \frac{m_1}{M} \\\\n_1 = \frac{4}{4} = 1

The number of moles of the gas when the reacting mass is 3.0 g;

m₂ = 3.0 g

n_2 = \frac{m_2}{M} \\\\n_2 = \frac{3}{4} \\\\n_2 = 0.75 \ mol

The volume of the gas at 0.75 mol is determined using ideal gas law;

PV = nRT

PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\since, \ \frac{RT}{P} \ is \ constant,\  then;\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1n_2}{n_1} \\\\V_2 = \frac{22.4 \times 0.75}{1} \\\\V_2 = 16.8 \ L

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.

4 0
3 years ago
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