Answer:
The magnitude of the magnetic force exerted on the moving charge by the current in the wire is 2.18 x N
The direction of the magnetic force exerted on the moving charge by the current in the wire is radially inward
Explanation:
given information:
current, I = 3 A
= +6.5 x C
r = 0.05 m
v = 280 m/s
and direction of the magnetic force exerted on the moving charge by the current in the wire, we can use the following formula:
F = qvB sin θ
where
F = magnetic force (N)
q = electric charge (C)
v = velocity (m/s)
θ = the angle between the velocity and magnetic field
to find B we use
B = μI/2πr
μ = 4π x or 1.26 x N/ , thus
B = 4π x x 3 / 2π(0.05)
= 1.2 x T
Now, we can calculate the magnitude force
F = qvB sin θ
θ = 90°, because the speed and magnetic are perpendicular
F = 6.5 x x 280 x 1.2 x sin 90°
= 2.18 x N
Using the hand law, the magnetic direction is radially inward
Not much changes, but there are some great pressure so some hills may form.
Answer:
371.2 mm
Explanation:
The Balmer series of spectral lines is obtained from the formula
1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹
when n = 15
1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)
= 1.097 × 10⁷ m⁻¹(1/4 -1/225)
= 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)
= 1.097 × 10⁷ m⁻¹ 0.245556
= 2.693 10⁶ m⁻¹
So,
λ = 1/2.693 10⁶ m⁻¹
= 0.3712 10⁻⁶ m
= 371.2 mm
Answer:
thermal and radiant
Explanation:
- thermal energy refers to the energy transmitted through heat
- radiant energy refers to the energy transmitted through electromagnetic radiation, such as light
When the person lights the match, the match produces both heat (thermal energy) and light (radiant energy), so the correct answer is
thermal and radiant