If a car traveled 60 m in 30 s, what is the velocity?*

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

1)

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

2)

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

3)

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

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3 0

3 years ago

Is scientific law and scientific theory the same?<br> True or false??<br><br> PLEASE HELP ME

VMariaS [17]

Is the sciencetjfic law and security theory the same?

TRUE

8 0

3 years ago

Read 2 more answers

Nanotechnology is currently used in electronics for

VMariaS [17]

Answer:

data storage, OLEDS, and wires

Explanation:

3 0

2 years ago

Explain how a rotating electric fan might be used to model the atom. explain how the rotating fan is unlike an atom.

quester [9]

A fan may be used to model an atom because the fan blades form something similar to a electron cloud. But there is really nothing to model the neutrons and protons. Also the fan is flat like where an atom is more 3-D sphere-like.

hope this helps

Ur welcome

have a great day (:

3 0

3 years ago

A square loop of wire, with sides of length a, lies in the first quadrant of the xy plane, with one corner at the origin. In thi

Ainat [17]

Answer:

$emf=-\dfrac{1}{2}kta^5$

Explanation:

Given that

B(y, t) = k y ³t²

To find the total flux over the loop we have to integrate over the loop

$\phi =\int B.dS$

Given that loop is square,so

$\phi =\int B.dS$

B(y, t) = k y ³t²

$\phi =kt^2\int_{0}^{a}dx\int_{0}^{a}y^3dy$

$\phi =\dfrac{1}{4}kt^2a^5$

We know that emf given as

$emf=-\dfrac{d\phi }{dt}$

$\phi =\dfrac{1}{4}kt^2a^5$

So

$emf=-\dfrac{1}{2}kta^5$

5 0

3 years ago