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kkurt [141]
4 years ago
13

Use the terms "force", "weight", "mass", and "inertia" to explain why it is easier to tackle a 220 lb football player than a 288

lb football player.
Physics
2 answers:
Tomtit [17]4 years ago
7 0
<span><u>Answer </u>
The mass of 220 lb football has less than 288 lb football. So, it will be easier to move it since it will require less force. The heavy football will have a bigger momentum. Since 288 lb has more weight than 220 lb, it will have bigger inertia making it difficult for the players to stop it.
This makes it easier to tackle 220 lb football than 288 lb football. 
</span>
Flura [38]4 years ago
6 0

There are several scientific aspects that require to be comprehended beforehand;

Force = mass * acceleration

Weight = mass * gravity (10m/s)

Momentum = mass * velocity

Inertia is a property of mass which is the tendency of an object to remain at constant velocity unless acted upon by an outside force.

Based on these formulae, it is evident that if the 220lb player and 288lb player are moving at the same velocity, the 288lb player has more inertia and momentum than the 22olb. Therefore, it would require more force (hence energy) to change the direction or the speed (in tackling) of the player with 288lb compared with what would be required on the 220lb player.

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A 225 kg block is pulled by two horizontal forces. The first force is 178 N at a 41.7-degree angle and the second is 259 N at a
yawa3891 [41]

Answer:

52.9 N, 364.7 N

Explanation:

First of all, we need to resolve both forces along the x- and y- direction. We have:

- Force A (178 N)

A_x = (178 N)(cos 41.7^{\circ})=132.9 N\\A_y = (178 N)(sin 41.7^{\circ})=118.4 N

- Force B (259 N)

B_x = (259 N)(cos 108^{\circ})=-80.0 N\\B_y = (259 N)(sin 108^{\circ})=246.3 N

So the x- and y- component of the total force acting on the block are:

R_x = A_x + B_x = 132.9 N - 80.0 N =52.9 N\\R_y = A_y + B_y = 118.4 N +246.3 N = 364.7 N

7 0
3 years ago
(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma
andrew11 [14]

Answer:

a) F=1.044\times 10^9\ N

b)F'=1.044\times 10^9\ N

c) F_p=1.0672\times10^{-7}\ N

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

  • mass of Mars, M=6.4\times 10^{23}\ kg
  • radius of the Mars, r=3.4\times 10^{6}\ m
  • mass of human, m=80\ kg

a)

Gravitation force exerted by the Mars on the human body:

F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
4 0
3 years ago
Qual a capacidade térmica de um objeto que, ao receber 10000 cal de energia, tem sua temperatura elevada de 25°C para 75°C?
Stolb23 [73]

Answer:

200 cal/^{\circ}C

Explanation:

When heat energy is supplied to an object, the temperature of the object increases according to the equation:

Q=C\Delta T

where

Q is the heat supplied

C is the heat capacity of the object

\Delta T is the change in temperature

In this problem we have:

Q=10,000 cal is the energy supplied

\Delta T=75C-25C=50C is the change in temperature of the object

Therefore, the heat capacity of the object is:

C=\frac{Q}{\Delta T}=\frac{10,000}{50}=200 cal/^{\circ}C

6 0
3 years ago
If we have less power, we most likely have
katrin [286]
<span>the same amount of work being done over a longer period of time.</span>
3 0
3 years ago
Read 2 more answers
Teams red and blue are having a tug-of-war. According to Newton's third law, the force with which the red team pulls on the blue
Zielflug [23.3K]
There are a few reasons that one teams could win. It depends if the on of the  teams has a better grip on the rope or not or maybe one off the teams has more friction between the ground and there shoes. So really it no matter what one of the teams will win.
7 0
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