The southernmost rim inlet elevation on the topographical survey is approximately 4.5 feet below the benchmark on the north side of West 55th Street.
What is topographical survey?
A topographical survey, often known as a land survey or topographical land survey, is a type of survey that includes contours. Topographical land surveying determines the exact location and specifications of natural and man-made features on a piece of land. The survey is then turned into a suitable and thorough plan, which incorporates man-made characteristics such as boundaries, neighbouring buildings, sidewalks, and so on. Natural elements such as trees, ponds, and ground contours are also detected by the topographical survey. Having a clear and accurate map of your property might help you avoid costly downstream mistakes caused by unforeseen challenges. It can supply you with the information you need about the land before making any alterations to it.
To learn more about topographical survey
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Answer:
atomic percentage = 143 %
Explanation:
Let x be the number of tin atoms and there are 4 atoms / cell in the FCC structure , then 4 -x be the number of copper atoms . Therefore, the value of x can be determined by using the density equation as shown below:
where;
the lattice parameter is given as : 4.7589 × 10⁻⁸ cm
The atomic mass of tin is 118.69 g/mol
The atomic mass of copper is 63.54 g/mol
The density is 8.772 g/cm³
569.32 = 118.69x + 254.16-63.54x
569.32 - 254.16 = 118.69x - 63.54 x
315.16 = 55.15x
x = 315.16/55.15
x = 5.72 atoms/cell
As there are four atoms per cell in FCC structure for the metal, thus, the atomic percentage of the tin is calculated as follows :
atomic % = 
atomic % = 
atomic % = 143 %
Answer:b
Explanation:
A beam is subjected to an upward load in the middle and supported in both ends. The upper fibers i.e. a topmost layer of the beam is in tension while bottom fiber i.e. fiber of bottom layer is in compression because they are under compressive force.
Fibers above the neutral axis are in tension and fibers below the neutral axis are in compression.
So option b is correct
