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Alecsey [184]
3 years ago
7

A 2.00 kg ball is thrown upward at Some unknown angle from the top of a 20.0 M high building If the initial magnitude of the vel

ocity of the ball is 20.0 MS what is the value of total energy
Physics
1 answer:
mixer [17]3 years ago
6 0

Answer:

792 J

Explanation:

The total energy of the ball is E = U + K where U = potential energy = mgh and K = kinetic energy = 1/2mv²

E = mgh + 1/2mv² where m = mass of ball = 2.0 kg, g = acceleration due to gravity = 9.8 m/s², h = height of building = 20.0 m, v = initial velocity of ball = 20.0 m/s.

So, substituting the values of the variables into E, we have

E = mgh + 1/2mv²

= 2.00 kg × 9.8 m/s² × 20.0 m + 1/2 × 2.00 kg × (20.0 m/s)²

=  392 J + 400 J

= 792 J

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igomit [66]

Answer;

- Line segment

Explanation;

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A vinyl record is played by rotating the record so that an approximately circular groove in the vinyl slides under a stylus. Bum
AleksandrR [38]

Answer:

Hits per second=199 hit/s

Explanation:

#Given the angular velocity, \omega=33\frac{1}{3} rev/min , radius of the record r=0.1m and the distance between any two successive bumps on the groove as d=1.75mm.

The linear speed of the record in meters per second is:

v=\omega r=33\frac{1}{3}\times\frac{2\pi}{60}\times 10\times 10^{_2}\\\\=0.3843m/s\\

#From v above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:

Hits/second=v/d    \ \ \ \ d=1.75mm\\\\=0.3483/0.000175\\\\=199.0385714\approx 199

Hence the bumps hit the stylus at around 199hit/s

8 0
3 years ago
What happens to the work done when a force is doubled and the distance moved remain the same?​
san4es73 [151]

Answer:

Work done gets doubled.

Explanation:

The work done by a force is given by :

W = Fd

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