Question

Around midcourse, a velocity adjustment is performed to eliminate the small errors introduced when departing from Earth's orbit. This adjustment is performed using one of the onboard thrusters. At the location where the adjustment is made, the velocity is 26248 m/s and should be 27000 m/s. Knowing that the thruster used for the maneuver generates a thrust of F= 7540 N, determine how long, in minutes, it should be turned on to adjust the velocity. The mass of the spacecraft is 2000 kg.

Answer 1

Answer:

Explanation:

Given:

Initial velocity, vi = 26248 m/s

Final velocity, vf = 27000 m/s

Force, f = 7540 N

Mass, m = 2000 kg

Force = mass × acceleration

= mass × change in velocity/time

Change in velocity = vf - vi

Time, t = (2000 × (27000 - 26248))/7540

= 199.47 s.

I min = 60 sec

Tine, t = 3.325 min

= 3.33 min.