Answer:
b = 5.164 m is the minimum thickness of the dam
Explanation:
Given
SG = 5
h = 20 m
b = ?
w = 1 m
γw = 9800 N/m³
We can get the forces as follows
Fp = γw*(h/2)*(h*w)
⇒ Fp = (9800 N/m³)*(20 m/2)*(20 m*1 m) = 1.96*10⁶N
W = (SG*γw)*(h*b*w)
⇒ W = (5*9800 N/m³)*(20 m*b*1 m) = (9.8*10⁵N/m)*b
Then, we apply
∑M₀ = 0 (counterclockwise)
- Fp*(h/3) + W*(b/2) = 0
⇒ - 1.96*10⁶N*(20 m/3) + (9.8*10⁵N/m)*b*(b/2) = 0
- 13.066*10⁶N-m + (4.9*10⁵N/m)*b² = 0
⇒ b = 5.164 m is the minimum thickness of the dam
I believe they would electron rate would slow down and the molecules would shrink.
I am almost positive that this is correct. I hope it helps!
Answer:
fixed pulley: A pulley system in which the pulley is attached to a fixed point and the rope is attached to the object. ... movable pulley: A pulley system in which the pulley is attached to the object; one end of the rope is attached to a fixed point and the other end of the rope is free.
Explanation:
Answer:
[1, 6, -2]
Explanation:
Given the following :
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Location of ship after two hours have passed :
Distance moved by spaceship :
Velocity × time
[-1 2 -3] × 2 = [-2 4 -6]
Location of ship after two hours :
Initial position + distance moved
[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6] = [1, 6, -2]
The answer is,
<u>Farthest from the axis of rotation</u>
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