Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before the collision, puck 1 is going 13 m/s to the east and
2 answers:
Answer:
13 m/s east
Explanation:
We can solve the problem by using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision:
where
m = 0.1 kg is the mass of each puck
u1 = +13 m/s is the initial velocity of puck 1
u2 = -18 m/s is the initial velocity of puck 2 (here I assume the west direction to be the negative direction, so I put a negative sign)
v1 = -18 m/s is the final velocity of puck 1
v2 = ? is the final velocity of puck 2
Simplifying m from the formula and substituting the data, we can find the final velocity of puck 2, v2:
And the positive sign means that puck 2 is moving east.
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Answer:
Negative acceleration
Explanation:
Let us assume a vehicle is moving with a constant velocity u and then it comes to a sudden stop.
The initial velocity of the vehicle is u and finally it comes to rest, it means final velocity is 0.
As we know that,
Acceleration is equal to change in velocity divided by time taken.
We can see that the value of acceleration is negative. Hence, it leads to negative acceleration.
Answer:
The magnitude of electric field is 22.58 N/C
Solution:
Given:
Force exerted in upward direction,
Charge, Q =
Now, we know by Coulomb's law,
Also,
Electric field,
Thus from these two relations, we can deduce:
F = QE
Therefore, in the question:
Here, the negative side is indicative of the Electric field acting in the opposite direction, i.e., downward direction.
The magnitude of the electric field is:
First we will use the concepts of motion kinetics for which the final speed is defined as shown below,
Here,
= Final velocity
= Initial velocity
a = Acceleration
s = Distance
Replacing,
Using the conservation of energy for kinetic energy we have,
Therefore the kinetic energy of the car is 31900J