1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
QveST [7]
3 years ago
7

Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before the collision, puck 1 is going 13 m/s to the east and

puck 2 is going 18 m/s to the west. After the collision, puck 1 is going 18 m/s to the west. What is the velocity of puck 2?
Physics
2 answers:
ohaa [14]3 years ago
4 0

Answer:

13 m/s east

Explanation:

We can solve the problem by using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision:

p_i = p_f \\m u_1 + m u_2 = m v_1 + m v_2

where

m = 0.1 kg is the mass of each puck

u1 = +13 m/s is the initial velocity of puck 1

u2 = -18 m/s is the initial velocity of puck 2 (here I assume the west direction to be the negative direction, so I put a negative sign)

v1 = -18 m/s is the final velocity of puck 1

v2 = ? is the final velocity of puck 2

Simplifying m from the formula and substituting the data, we can find the final velocity of puck 2, v2:

v_2 = u_1 + u_2 - v_1 = +13 m/s + (-18 m/s) - (-18 m/s) = +13 m/s

And the positive sign means that puck 2 is moving east.

Amanda [17]3 years ago
4 0
According to the law of conservation of momentum,
m1u1 + m2u2 = m1v1 + m2v2
0.1 x 13 + 0.1 x 18 = 0.1 x 18 + 0.1 x v2
v2 = 13 m/s
the velocity of puck 2 is 13 m/s
You might be interested in
A step-down transformer has 2500 turns on its primary and 5.0 x 10' tums on its secondary. If the potential difference across th
Brilliant_brown [7]

Answer:

I dont know sorry

Explanation:

hehe

4 0
3 years ago
Freezing Point Depression: Can someone explain this formula to me? ΔTf = Kfcm
Leya [2.2K]
If the solution is treated as an ideal solution, the extent of freezing point depression depends only on the solute concentration that can be estimated by a simple linear relationship with the cryoscopic constant: ΔTF = KF · m · i ΔTF, the freezing point depression, is defined as TF (pure solvent) - TF (solution). KF, the cryoscopic constant, which is dependent on the properties of the solvent, not the solute. Note: When conducting experiments, a higher KF value makes it easier to observe larger drops in the freezing point. For water, KF = 1.853 K·kg/mol.[1] m is the molality (mol solute per kg of solvent) i is the van 't Hoff factor (number of solute particles per mol, e.g. i = 2 for NaCl).
8 0
3 years ago
A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0
3 years ago
How are dwarf planets different from true planets?
morpeh [17]

Answer:

The only difference between a planet and a dwarf planet is the area surrounding each celestial body. A dwarf planet has not cleared the area around its orbit, while a planet has.

Explanation:

the three criteria of the IAU for a full-sized planet are: It is in orbit around the Sun. It has sufficient mass to assume hydrostatic equilibrium (a nearly round shape). It has "cleared the neighborhood" around its orbit .

3 0
3 years ago
If you were trying to build a soundproof room, which of the following materials would you choose in order to absorb the most sou
leonid [27]

Explanation :  

Absorption coefficient of a material determines how much sound is absorbed by the material.

To build a soundproof room, Heavy curtains and carpet can be used. They reduce reverberation.

Reverberation means an echoing sound which persists for some time. For example, when we bang on a huge piece of metal, we hear the reverberation even after we stop banging.  

Hence, option (A) and (D) are correct.

5 0
4 years ago
Read 2 more answers
Other questions:
  • Weight is a force that depends on mass and: *
    11·2 answers
  • What is the longest wavelength of radiation with enough energy to break carbon-carbon bonds?
    9·1 answer
  • Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y =
    5·2 answers
  • A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 4.0 cm from the axis of rotation. (a) Calcul
    9·1 answer
  • From the edge of a cliff, a 0.46 kg projectile is launched with an initial kinetic energy of 1430 J. The projectile's maximum up
    15·1 answer
  • hi everyone im learning about zodiac signs can u plz share urs and somethings u like to for ex im an aquarius and i sing and lik
    5·2 answers
  • Calculate the mass of a planet that exerts a 1.5 X 10 13 N force on a 5.4 x 10
    14·2 answers
  • The difference between an electric motor and an electric generator is that a motor converts _______ energy into energy _______,
    9·2 answers
  • Can someone please explain some calculations on vernier calliper​
    7·2 answers
  • Just a question anybody playing minècraft here?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!