Out of all given choices, “Different samples have different properties” is not a characteristic of a compound
Answer: Option A
<u>Explanation:
</u>
A substance which comprises of more than one element chemically linked together at a fixed weight ratio usually referred as compound. The relationship arises due to the result of the chemical reactions between the components of the elements.
The property of the compound vary from the property of its elements to which it gets formed. For example: Water (
) is a combination of two elements, hydrogen and oxygen, chemically bonded in a constant 1: 8 weight ratio
.
i think the image in the attachment does...
hope it helps...!!!
Explanation:
Given:
![r_a = 3.570R_E](https://tex.z-dn.net/?f=r_a%20%3D%203.570R_E)
![R_E = 1.499×10^{11}\:\text{m}](https://tex.z-dn.net/?f=R_E%20%3D%201.499%C3%9710%5E%7B11%7D%5C%3A%5Ctext%7Bm%7D)
![M_S = 1.989×10^{30}\:\text{kg}](https://tex.z-dn.net/?f=M_S%20%3D%201.989%C3%9710%5E%7B30%7D%5C%3A%5Ctext%7Bkg%7D)
![G = 6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2](https://tex.z-dn.net/?f=G%20%3D%206.674%C3%9710%5E%7B-11%7D%5C%3A%5Ctext%7BN-m%7D%5E2%5Ctext%7B%2Fkg%7D%5E2)
Let
= mass of the asteroid and
= orbital radius of the asteroid around the sun. The centripetal force
is equal to the gravitational force ![F_G:](https://tex.z-dn.net/?f=F_G%3A)
![F_c = F_G \Rightarrow m_a\dfrac{v_a^2}{r_a} = G\dfrac{m_aM_S}{r_a^2}](https://tex.z-dn.net/?f=F_c%20%3D%20F_G%20%5CRightarrow%20m_a%5Cdfrac%7Bv_a%5E2%7D%7Br_a%7D%20%3D%20G%5Cdfrac%7Bm_aM_S%7D%7Br_a%5E2%7D)
or
![\dfrac{4\pi^2 r_a}{T^2} = G\dfrac{M_S}{r_a^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%5Cpi%5E2%20r_a%7D%7BT%5E2%7D%20%3D%20G%5Cdfrac%7BM_S%7D%7Br_a%5E2%7D)
where
![v = \dfrac{2\pi r_a}{T}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B2%5Cpi%20r_a%7D%7BT%7D)
with T = period of orbit. Rearranging the variables, we get
![T^2 = \dfrac{4\pi^2 r_a^3}{GM_S}](https://tex.z-dn.net/?f=T%5E2%20%3D%20%5Cdfrac%7B4%5Cpi%5E2%20r_a%5E3%7D%7BGM_S%7D)
Taking the square root,
![T = 2\pi \sqrt{\dfrac{r_a^3}{GM_S}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cdfrac%7Br_a%5E3%7D%7BGM_S%7D%7D)
![\:\:\:\:=2\pi \sqrt{\dfrac{(3.57(1.499×10^{11}\:\text{m}))^3}{(6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2)(1.989×10^{30}\:\text{kg})}}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%3D2%5Cpi%20%5Csqrt%7B%5Cdfrac%7B%283.57%281.499%C3%9710%5E%7B11%7D%5C%3A%5Ctext%7Bm%7D%29%29%5E3%7D%7B%286.674%C3%9710%5E%7B-11%7D%5C%3A%5Ctext%7BN-m%7D%5E2%5Ctext%7B%2Fkg%7D%5E2%29%281.989%C3%9710%5E%7B30%7D%5C%3A%5Ctext%7Bkg%7D%29%7D%7D)
![\:\:\:\:= 2.13×10^8\:\text{s} = 6.75\:\text{years}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%3D%202.13%C3%9710%5E8%5C%3A%5Ctext%7Bs%7D%20%3D%206.75%5C%3A%5Ctext%7Byears%7D)
Answer: A: false
Explanation:
And object will weigh less on the moon because the moons gravity is weaker than Earths gravity.
Answer: E = 941738.537J
Explanation:
to begin,
given that the mass = 2320 pound = 1052.334 kg
Δh = 110 ft = 33.528 m
given that distance (d) = 1283 ft = 391.058 m
also the speed (v) is 65 mph = 29.058 m/s
force (F) = 87 pounds = 386.995 N
from our knowledge in work energy theory;
E = Fd + 1/2mv² + mgh
E = (386.995 × 391.058) + (1/2×1052.334×29.058²) + (1052.334×9.81×33.528)
E = 151337.491 + 444278.2 + 346122.84
E = 941738.537J
i hope this helps, cheers.