Question

What mass of electrons would be required to just neutralize the charge of 5.0 g of protons? (the mass of a proton is 1.67262×10−24g, and the mass of an electron is 9.1×10−28g.)?

Answer 1

To  neutralize the charge of 1.0g of electrons?

Answer 2

Answer:

$m = 2.72 \times 10^{-3} g$

Explanation:

total number of protons in 5 gram of total mass is given as

$N = \frac{m}{m_p}$

here we have

$N = \frac{5}{1.67262 \times 10^{-24}}$

$N = 2.99 \times 10^{24}$

now to neutralize the charge we require same amount of negatively charge electrons

so we have

$m = N(m_e)$

$m = (2.99 \times 10^{24})(9.1 \times 10^{-28})$

$m = 2.72 \times 10^{-3} g$