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Anit [1.1K]
3 years ago
6

Monday Homework Problem 10.6 A simple generator is constructed by rotating a flat coil in a uniform magnetic field. Suppose we r

otate a flat coil of radius 2.0cm and 400 turns in the earth’s magnetic field 6 times per second so that the surface normal to the coil is parallel to the field once per revolution. The earth’s magnetic field is still about 4 × 10−5T. What is the maximum emf that would be measured acro
Physics
1 answer:
prohojiy [21]3 years ago
8 0

Our values are,

B=1*10^{-5}T

N=400

r = 2.0cm = 0.02 m

Number of rotations per second = 6

We begin calculating the cross-section Area, which is given by,

A= \pi r^2

A= \pi (0.02)^2

A= 1.2566*10^{-3} m^2

We can calculate the angular speed through the number of rotations per second,

\omega = 6 rev

\omega = 6(\frac{2}{pi})

\omega =37.699 rad/s

With this velocity we can now calculate the maximum emf,

E= BAN\omega

E = (4*10^{-5})(1.2566*10^{-3})(400)(37.699)

E= 7.579*10^{-4} V

E= 7.6*10^{-4} V

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faltersainse [42]

Answer: By 47

Explanation: subtract 310 and 263

6 0
3 years ago
The per-unit impedance of a single-phase electric load is 0.3. The base power is 500 kVA, and the base voltage is 13.8 kV. a. Fi
Leto [7]

Answer:

114.26

Explanation:

a)Formula for per unit impedance for change of base is

Zpu2= Zpu1×(kV1/kV2)²×(kVA2/kVA1)

Zpu2: New per unit impedance

Zpu1: given per unit impedance

kV1: give base voltage

kV2: New bas votlage

kVA1: given bas power

kVA2: new base power

In the question

Zpu2=??

Zpu1= 0.3

kV2=24kV

kV1= 13.8 kV

kVA2= 1MVA ×1000= 1000 kVA

kVA1=500kVA

Zpu2= 0.3(13.8/24)²×(1000/500)

Zpu2= 0.198

b) to find ohmic impedance we will first calculate base value of impedance(Zbase). So,

Zbase= kV²/MVA

  Zbase= 13.8²/(500/1000)

  Zbase=380.88

Now that we have base value of impedance, Zbase, we can calculate actual ohmic value of impedance(Zactual) by using the following formula:

Zpu=Zactual/Zbase

0.3= Zactual/380.88

Zactual= 114.26 ohms

8 0
3 years ago
A cellist tunes the C string of her instrument to a fundamental frequency of 65.4 Hz. The vibrating portion of the string is 0.5
Dahasolnce [82]

Answer:

a

\lambda  = 1.18 \  m

b

v  =  77.172 \  m/s

c

T  = 151.41 \  N

Explanation:

From the question we are told that

   The frequency is  f =  65.4 \  Hz

   The  length of the vibrating string is  L  =  0.590 \  m

   The  mass is  m  =  15.0 \ g  =  0.015 \  kg

Generally the wavelength is mathematically represented as

           \lambda =  2 *  L

=>        \lambda  =  2 *   0.590

=>         \lambda  = 1.18 \  m

Generally the wave speed is  

          v  =  \lambda  *  f

=>       v  =  1.18 * 65.4

=>       v  =  77.172 \  m/s

Generally the tension on the wire is mathematically represented as

        T  =  v^2  *  \frac{ m }{L }

=>      T  =  77.172 ^2  *  \frac{  0.015  }{0.590}

=>      T  = 151.41 \  N

7 0
3 years ago
The speed of sound in wood is ____ the speed of sound in water.
pishuonlain [190]

Answer:

greater

Explanation:

the speed of sound in steel is greater than water. the speed of sound in wood is not, In water, the particles are much closer together, and they can quickly transmit vibration energy from one particle to the next. This means that the sound wave travels over four times faster than it would in air, but it takes a lot of energy to start the vibration.

Wood is less dense and force can make a sound.

8 0
3 years ago
a glass beaker has a mass of 50g. a liquid of density 1.8g/cm3 is poured into the beaker until it reaches the 200cm3 mark. calcu
xz_007 [3.2K]

<u>Answer:</u>

total mass = 410 g

<u>Explanation:</u>

density = 1.8 g/cm³

volume = 200 cm³

                              density = mass / volume

                              mass (of liquid) = density   x    volume

                                        = 1.8 x 200

                                        = 360 g

          total mass (beaker + liquid) = 50 + 360 = 410 g     [Ans]

Hope this helps!

5 0
3 years ago
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