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klemol [59]
3 years ago
13

A cheetah accelerates from rest to 30m/s in 3 seconds. Calculate the acceleration of the cheetah.

Physics
1 answer:
fiasKO [112]3 years ago
4 0
30m/s times 3s= 90 m/s
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aniked [119]

Answer:

Blank = Increase

4 0
2 years ago
I need help pleaseee
Ludmilka [50]

Answer:

8) 709.8875 J

9) The object is at 7.24375 m from the ground

10) Kinetic energy increases as the object falls.

Explanation:

We use the expression for the displacement h(t) as a function of time of an object experiencing free fall:

h(t) = hi - (g/2) t^2

hi being the initial position of the object (10m) above ground, g the acceleration of gravity (9.8 m/s^2), and t the time (in our case 0.75 seconds):

h(0.75) = 10 - 4/9 (0.75)^2 = 7.24375 m

This is the position of the 10 kg object after 0.75 seconds (answer for part 9)

Knowing this position we can calculate the potential energy of the object when it is at this height, using the formula:

U = m g h = 10kg * 9.8 (m/s^2) * 7.24375 m = 709.8875 J (answer for part 8)

Part 10)

the kinetic energy of the object increases as it gets closer to ground, since its velocity is increasing in magnitude because is being accelerated in its motion downwards.

3 0
3 years ago
5. Suppose that you wish to construct a simple ac generator having an output of 24 V maximum when rotated at 120 Hz. A uniform m
vazorg [7]

Answer:

32 turns

Explanation:

From the expression for the induced emf,

E = (N)(B)(A) w

E = emf = 24 V

N = number of turns = ?

B = magnetic field strength = 0.10 T

A = Cross sectional Area of the loop = 100 cm² = 0.01 m²

w = Angular speed = (2πf) = (2π × 120) = 754.3 rad/s

24 = N (0.1)(0.01)(754.3)

N = (24/0.7543)

N = 31.8 ≈ 32 turns.

Hope this Helps!!!

6 0
3 years ago
A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance th
____ [38]
The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."

In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
F=G \frac{Mm}{d^2}
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
3 0
3 years ago
In calisthenics, the resistance is ultimately provided by __________. A. free weights B. springs and elastic bands C. gravity D.
tangare [24]

Answer:

I think the answer is b am sorry if it is wrong

Explanation:

5 0
2 years ago
Read 2 more answers
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