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klemol [59]
3 years ago
13

A cheetah accelerates from rest to 30m/s in 3 seconds. Calculate the acceleration of the cheetah.

Physics
1 answer:
fiasKO [112]3 years ago
4 0
30m/s times 3s= 90 m/s
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BLANK causes movement of an object, whereas BLANK is the work done on an object in a given amount of time.
Setler [38]
The first one is Force & the second one Power.
3 0
4 years ago
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an object is placed 15.8 cm in front of a thin converging lens with an unknown focal length. if a real image forms behind the le
storchak [24]
<span>On what:

f (is the focal length of the lens) = ? 
p (is the distance from the object to the lens) =15.8 cm
p' (is the distance from the image to the spherical lens) = 4.2 cm

</span><span>Using the Gaussian equation, to know where the object is situated (distance from the point).
</span>
\frac{1}{f} = \frac{1}{p} + \frac{1}{p'}
\frac{1}{f} = \frac{1}{15.8} + \frac{1}{4.2}
\frac{1}{f} = \frac{2.1}{33.18} + \frac{7.9}{33.18}
\frac{1}{f} =  \frac{10}{33.18}
Product of extremes equals product of means:
10*f = 1*33.18
10f = 33.18
f =  \frac{33.18}{10}
\boxed{\boxed{f = 3.318\:cm}}\end{array}}\qquad\quad\checkmark

6 0
4 years ago
You are an engineer in charge of designing a new generation of elevators for a prospective upgrade to the Empire State Building.
DanielleElmas [232]

Answer:

   t_total = 23.757 s

Explanation:

This is a kinematics exercise.

Let's start by calculating the distance and has to reach the limit speed of

v = 18.8 m / s

         v = v₀ + a t₁

the elevator starts with zero speed

         v = a t₁

         t₁ = v / a

         t₁ = 18.8 / 2.40

         t₁ = 7.833 s

in this time he runs

         y₁ = v₀ t₁ + ½ a t₁²

         y₁ = ½ a t₁²

         y₁ = ½ 2.40 7.833²

         y₁ = 73.627 m

This is the time and distance traveled until reaching the maximum speed, which will be constant throughout the rest of the trip.

           x_total = x₁ + x₂

           x₂ = x_total - x₁

           x₂ = 373 - 73,627

           x₂ = 299.373 m

this distance travels at constant speed,

           v = x₂ / t₂

           t₂ = x₂ / v

           t₂ = 299.373 / 18.8

           t₂ = 15.92 s

therefore the total travel time is

           t_total = t₁ + t₂

           t_total = 7.833 + 15.92

           t_total = 23.757 s

6 0
3 years ago
Which graphs show the correct relationship between kinetic energy and mass?
Anettt [7]
Kinetic Energy:
Kinetic Energy is the energy of motion.

Mass:
Mass is the number of particles that a substance has


I think the correct graph would be
the THIRD GRAPH
5 0
3 years ago
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A cannon is mounted on a tower above a wide, level field. The barrel of the cannon is 20 m above the ground below. A cannonball
OLga [1]

<u>Answer:</u>

  Cannonball will be in flight before it hits the ground for 2.02 seconds

<u>Explanation:</u>

  Initial height from ground = 20 meter.

  We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 m/s^2, we need to calculate time when s = 20 meter.

  Substituting

         20=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.02 seconds

  So it will take 2.02 seconds to reach ground.

5 0
3 years ago
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