Hey there!
1 mole has 6.022 x 10²³ atoms.
Multiply that by 3.2 because we have 3.2 moles.
3.2 x 6.022 x 10²³
1.9 x 10²⁴
There are 1.9 x 10²⁴ atoms in 3.2 moles of chromium.
Hope this helps!
Answer:
b. forest ....
I think ansesters also lived in forest by wearing leaves like their clothes .... etc
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
I believe the correct order of words should be:
Counterclockwise
Crescent
Full
Half
Faces?
Waxing
Right
Waning
Left
I am not sure on faces, but I don't see any other words from the bank that would fit that description. Hope these are correct and hope I helped!
Answer: D) It has two more electrons than protons.
Explanation: Sulphur (S) is an element with atomic number 16 and thus contains 16 electrons. A neutral atom contains equal number of protons and electrons.
![S:16:[Ne]3s^23p^4](https://tex.z-dn.net/?f=S%3A16%3A%5BNe%5D3s%5E23p%5E4)
An atom on losing electrons gains positive charge and on gaining electrons gain negative charge.
Sulphide ion
is formed by gaining 2 electrons to attain stable configuration of argon and thus contains two more electrons than protons.
![S^{2-}:18:[Ne]3s^23p^6:[Ar]](https://tex.z-dn.net/?f=S%5E%7B2-%7D%3A18%3A%5BNe%5D3s%5E23p%5E6%3A%5BAr%5D)