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3 years ago

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An x-ray beam with wavelength 0.170 nm is directed at a crystal. As the angle of incidence increases, you observe the first stro

ng interference maximum at an angle 62.5 ∘. What is the spacing d between the planes of the crystal?

1 answer:

xeze [42]3 years ago

3 0

The distance between the scattering planes in the crystal is d = 0.95 A°

<u>Explanation</u>:

The Bragg's equation is given by

2d sinθ = nλ

where,

d is the distance between the scattering planes in the crystal.

θ is the angle of diffraction.

n is the order of diffraction.

λ is the wavelength of X rays.

Given λ = 0.17 nm = 1.7 A°, angle = 62.5

2 $\times$ d $\times$ sin(62.5) = 1 $\times$ 1.7 A°

d = 0.95 A°

The distance between the scattering planes in the crystal is d = 0.95 A°

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