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Svetach [21]
3 years ago
5

Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree Celcius.

Physics
2 answers:
MArishka [77]3 years ago
8 0
Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree Celsius.

Answer: In order to calculate the average translational kinetic energy of a nitrogen molecule at 27 degrees celcius we will have to use the following formula: Average Translational KE molecule = (3/2)*1.38*10^-23 J/K× T. First we convert the 27 degrees celsius to kelvin. Which should give you 300.15. Now we simply replace it in the formula and you should get 6.213104999999999e-21.

I hope it helps, Regards.
Molodets [167]3 years ago
7 0
T = 27° C = 27 + 273 = 300 K
Bolzmann constant: k b = 1.38065 · 10^(-22) J/K
K = 3/2 kb T
K = 3/2 · 1.38065 · 10^(-22) J/K · 300 K = 6.212925 · 10^(-20) J
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You have a mass of 95 kg.<br> a. What is your weight on Earth?
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3 years ago
A student falls off a cliff into the lake 54.0 m below. What is the final velocity of the student?
Vladimir79 [104]

Answer:

v_{y} = -32.53 m / s

this velocity is directed downwards

Explanation:

This is a free fall exercise, let's use the expression

         v_{y}^{2} = v_{oy}^{2} + 2 g (y -yo)

where we are assuming that there is friction with the air, as the body falls its initial velocity is zero

         v_{oy} = √ 2g (y - y₀)

let's calculate

         v_{y} = √ (2 9.8 (0-54.0))

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6 0
4 years ago
You stand on a merry-go-round which is spinning at f = 0.25 revolutions per second. You are R = 200 cm from the center. (a) Find
wariber [46]

Answer:

a) ω = 9.86 rad/s

b) ac = 194. 4 m/s²

c) minimum coefficient of static friction, µs = 19.8

Explanation:

a) angular speed, ω = 2πf, where f is frequency of revolution

1 rps = 6.283 rad/s, π = 3.142

ω = 2 * 3.14 * 0.25 * 6.28

ω = 9.86 rad/s

b) centripetal acceleration, a = rω²

where r is radius in meters; r = 200 cm or 2 m

a = 2 * 9.86²

a = 194. 4 m/s²

c) µs = frictional force/ normal force

frictional force = centripetal force = ma; where a is centripetal acceleration

normal force = mg; where g = 9.8 m/s²

µs = ma/mg = a/g

µs = 194.4 ms⁻²/9.8 ms⁻²

c) minimum coefficient of static friction, µs = 19.8

5 0
3 years ago
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