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Virty [35]
3 years ago
9

11. How many grams of O2 are required to produce 36.9 grams of ZnO? 22n +102 → 2ZnO

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0

Answer:

Mass = 7.2 g

Explanation:

Given data:

Mass of ZnO = 36.9 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

2Zn + O₂ → 2ZnO

Number of moles of ZnO:

Number of moles = Mass/ molar mass

Number of moles = 36.9 g/81.38 g/mol

Number of moles = 0.45 mol

Now we will compare the moles of ZnO with oxygen:

                      ZnO           :           O₂

                         2             :            1

                      0.45           :       1/2 × 0.45 = 0.225

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.225 mol × 32 g/mol

Mass = 7.2 g

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Answer:

5.995 psi

Explanation:

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3 years ago
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Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

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Hence;

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Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

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Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

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3 years ago
For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4?
jekas [21]
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3 years ago
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HACTEHA [7]

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3 0
3 years ago
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zmey [24]

Answer:

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2 years ago
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