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Trava [24]
3 years ago
11

Which ONE of the following compounds is least soluble in water?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

B) CH3CH2CH2F

Explanation:

All the other compounds listed among the options are capable of forming hydrogen bonds with water except CH3CH2CH2F.

Recall that hydrogen bonds are formed when hydrogen is directly bonded to a highly electronegative atom such as nitrogen, oxygen, fluorine, sulphur, et cetra.

Such bonds are not present in CH3CH2CH2F, rather fluorine is bonded to carbon to give a halogenoalkane. This compound will display the least solubility in water.

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Our current model of a chemical bond is to think of it as an electrical interaction between what two parts of an atom
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Explanation:

It involves the thinking of it as an electrical interaction between the positively charged part of an atom and the negatively charged part as well. Succinctly put, the interaction between the proton of an atom and the electron of an atom.

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A sample of helium gas is in a sealed rigid container. What occurs as the temperature of the sample is increased
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The electrons will move more rapidly resulting in a higher pressure even at a consistent volume
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3 years ago
If a young girl learned that it would be 0° C, or 32° F, the next
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7 0
3 years ago
A solution of barium nitrate has 61.2g of barium nitrate in 1 liter of solution. How many mg of barium are there in 7.5 quarts
Nuetrik [128]

Answer:

220.44g Ba²⁺ ions in solution

Explanation:

Given parameters:

Mass of barium nitrate = 61.2g

Volume of solution = 1 liter

Unkown:

Mass of barium in 7.5quarts of solution?

Solution

We must first convert quarts to its liter equivalence:

                    1 quarts = 0.95 liter

                   7.5 quarts = 0.95 x 7.5; 7.125liter

Now, let us find the mass of barium nitrate in a solution of 7.125liter:

        Given:

            1 liter of solution contains 61.2g of barium nitrate:

          7.125 liter will contain  7.125 x 61.2 = 436.05g of barium nitrate.

The formula of the compound is Ba(NO₃)₂:

  In solution we have  Ba²⁺ + NO₃⁻

                Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻

 

Number of moles of Ba(NO₃)₂ = \frac{mass of Ba(NO₃)₂}{Molar mass of Ba(NO₃)₂}

Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol

Number of moles of Ba(NO₃)₂ = \frac{436.05}{271} = 1.609mole

      1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution

    therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution

Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions  x molar mass of Ba²⁺ ions

Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g

3 0
3 years ago
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