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alukav5142 [94]
3 years ago
6

Low-level coding means that...

Engineering
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

a.) a component item is coded at the lowest level at which it appears in the BOM structure is the correct answer.

Explanation:

  • Low-level coding is a kind of programming language used in BOM structures and it carries basic commands that are identified by a computer.
  • The two types of low-level coding are
  • Assembly language.
  • machine language.
  • The advantages of using low-level coding are programs develop by using low-level code are very memory effective and quick and there no need to use interpreters for the conversion of the source to machine code.
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A single Gates Rubber V belt is to be selected to deliver engine power to the wheel-drive transmission of a riding tractor. A 5-
beks73 [17]

Answer:

Hello there, please check step by step explanations to get answers.

Explanation:

Given that:

5-hp single-cylinder engine is used. At most, the belt transmits 60 percent of this power. The driving sheave has a diameter of 6.2 in. and the driven, 12.0 in. The belt selected should be as close to 92 in pitch length as possible. The engine speed is governor-controlled to a maximum of 3100 rev/min. Select a satisfactory belt, and specify it using the standard designation.

See attached documents for clearity and step by step procedure to answer

7 0
3 years ago
A plate (A-C) is connected to steelflat bars by pinsat A and B. Member A-E consists of two 6mm by 25mm parallel flat bars. At C,
juin [17]

Answer:

stress_ac = 5.333 MPa

shear stress_c = 1.763 MPa

Explanation:

Given:

- The missing figure is in the attachment.

- The dimensions of member AC = ( 6 x 25 ) mm x 2

- The diameter of the pin d = 19 mm

- Load at point A is P = 2 kN

Find:

-  Find the axial stress in AE and the shear stress in pin C.

Solution:

- The stress in member AE can be calculated using component of force P along the member AE  as follows:

                                    stress_ac = P*cos(Q) / A_ae

Where, Angle Q: A_E_B   and A_ac: cross sectional area of member AE.

                                    cos(Q) = 4 / 5   ..... From figure ( trigonometry )

                                    A_ae = 0.006*0.025*2 = 3*10^-4 m^2

Hence,

                                    stress_ae = 2*(4/5) / 3*10^-4

                                    stress_ae = 5.333 MPa

- The force at pin C can be evaluated by taking moments about C equal zero:

                                   (M)_c = P*6 - F_eb*3

                                      0 = P*6 - F_eb*3

                                      F_eb = 0.5*P

- Sum of horizontal forces for member AC is zero:

                                      P - F_eb - F_c = 0

                                      F_c = 0.5*P

- The shear stress of double shear bolt is given by an expression:

                                     shear stress = shear force / 2*A_pin

Where, The area of the pin C is:

                                     A_pin = pi*d^2 / 4

                                     A_pin = pi*0.019^2 / 4 = 2.8353*10^-4 m^2

Hence,

                                     shear stress = 0.5*P / 2*A_pin

                                     shear stress = 0.5*2 / 2*2.8353*10^-4

                                    shear stress = 1.763 MPa

7 0
3 years ago
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klemol [59]

Answer:true

Explanation:

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A heated plate is built into the wall of a large room. The room is maintained at 300 K. The exposed surface of the plate is main
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Answer:

B

Explanation:

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Rockfalls can cause major damage to roads and infrastructure. To design mitigation bridges and barriers, engineers use the coeff
Rus_ich [418]

Answer:

Velocity of rock fall collision, v = 13.21 m/sec

Explanation:

Detailed explanation given in the attached document.

5 0
3 years ago
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