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Dmitriy789 [7]
3 years ago
15

The acceleration due to gravity on Mars is less than that on Earth. On Mars, a person will weigh than on Earth.

Physics
2 answers:
pantera1 [17]3 years ago
4 0
On mars people would way less. 
An example of this is that if I weighed 700 pounds (I don't by the way) I would then weigh 500 pounds or less.

Vlad [161]3 years ago
4 0

Answer:  On Mars, a person will weigh <u>less</u> than on Earth.

Explanation:

The mass of the planet Mars is less than Earth. Because of this it pulls the objects on it with less force and thus Mars has less value of acceleration due to gravity.

The weight of the object is given by the product of mass and acceleration due to gravity.

W = m g'

W ∝ g'

The mass remains constant irrespective of the planet but weight varies with the value of acceleration due to gravity. Thus, on Mars, a person will weigh less than on Earth.

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A swimming pool is 25.0 ft. long, 18.5 ft. wide, and 9.0 ft. deep. When filled, the water level is 7.0 inches from the top. Disi
GarryVolchara [31]

Answer:

1.9841256 kg

Explanation:

Given;

Length of the swimming pool = 25.0 ft = 7.62 m   ( 1 ft = 0.3048 m )

Width of the swimming pool = 18.5 ft =  5.64 m

Depth of the pool = 9.0 ft =

Total depth of the water in the pool when filled = 9 ft - 7 inches = 2.56 m

now,

Volume of the water in the pool = Length × Width × Depth

or

Volume of the water in the pool = 7.62 × 5.64 × 2.56 = 110.2292 m³

also,

1 m³ = 1000 L

thus,

110.2292 m³ = 110229.2 L

also it is given that 18 mg of Cl is added to 1 liter of water

therefore,

In 110229.2 L of water Cl added will be = 110229.2 × 18 = 1984125.6 mg

or

= 1.9841256 kg

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4 years ago
A hot metal washer is placed in a jar of cool water.
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As a science fair project, you want to launch an 950 g model rocket straight up and hit a horizontally moving target as it passe
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Answer:

As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?

= 43.56m

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acceleration =

(20 - (0.95 * 9.8) )/ (0.95)

= 10.68 / 0.95

= 11.24 m/s²

we use

s = ut + (1/2) at²

Given that

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hence

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5 0
3 years ago
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