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PIT_PIT [208]
3 years ago
9

I need help with one - seven

Physics
2 answers:
vesna_86 [32]3 years ago
6 0

Answer:

Motion

Explanation:

Newton's first law is motion

igor_vitrenko [27]3 years ago
4 0

1.  inert<u><em>i</em></u>a

2. dis<u><em>t</em></u>ance

3. displace<u><em>m</em></u>ent

4. f<u><em>o</em></u>rce

5. bala<u><em>n</em></u>ced

6. I think it's looking for 'velocity', but the clue is an incorrect definition.

7. motion

I'm surprised that you couldn't answer any of these.

Please don't use these answers from me to fill in the blanks on the sheet and then hand it in.  It's a mastery test, and you have not mastered this material.

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You test it over and over again. so basically you experiment on it more. 
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If the temperature of a gas is increased by 10x, what will happen to the volume?
xxMikexx [17]

The volume of a gas will increase by ten times if the temperature is increased by ten times.

<h3>Relationship between the volume of a gas and temperature</h3>

The relationship between the volume of a gas and its temperature is explained in Charles' law of gases which states that:

  • The volume of a fixed mass of gas is directly proportional to its temperature provided the pressure of the gas is kept constant.

This means that if the temperature of a gas is increased by any given factor, the volume increases by the same factor proportionally.

Therefore, if the volume of a gas will increase by ten times if the temperature is increased by ten times.

Learn more about gas volume and temperature at: brainly.com/question/18706379

8 0
3 years ago
A solid metal sphere with radius 0.430 m carries a net charge of 0.270 nC . Part A Find the magnitude of the electric field at a
rodikova [14]

Answer:

8.46 N/C

Explanation:

Using Gauss law

E=\frac {kQ}{r^{2}}

Gauss's Law states that the electric flux through a surface is proportional to the net charge in the surface, and that the electric field E of a point charge Q at a distance r from the charge

Here, K is Coulomb's constant whose value is 9\times 10^{9} Nm^{2}/C^{2}

r = 0.43 + 0.106 = 0.536 m

E=\frac {9\times 10^{9}\times 0.270\times 10^{-9}}{0.536^{2}}=8.4581755402094007\approx 8.46 N/C

8 0
4 years ago
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