The radii of most atoms are actually measured in the Ǻ, or Angstrom. We can do it in nanometers too, however.
<span>First, we take the radius of the smallest atom, He (Helium). Atomic radius = .031 nm. The largest atom, stable atom is Fr (Francium), with atomic radius = .27 nm. </span>
<span>Therefore, the typical atomic radius is between .031 and .27 nm.</span>
Mv^2 = const
<span>m ~ 1/v^2 </span>
<span>(4.5/10.1)^2 = 0.198 </span>
<span>20.2 * 0.198 = 4.0 g/mol (Helium)</span>
Cesium.
Groups are the vertical columns that run up and down while periods are the horizontal rows. So to find the answer to this, go to the first column (Group 1) and find the sixth period (row 6) which will land you on Cesium, element 55.
Hope this helps!
There are one antibonding molecular orbitals present in molecular orbital model of c.
The cyclobutadiene has a pi system comprised of four individual atomic p - orbital and thus should have a four pi molecular orbitals. The compound is the prototypical antiaromatic hydrocarbon with 4 
- electrons . Its rectangular structure is the result of jahn teller reaction which disorder the molecule and lowers its symmetry , converting the triplet to a singlet ground state. It is a small annulene . The delocalisation energy of the electrons of the cyclobutene is predicted to be zero .
To learn more about antibonding molecular orbitals click here
brainly.com/question/14970060
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Just divide the two (2 / 0.05) and you will get your answer; there are 40 drops of bloodin the collection tube.
